Spring - JPA - 读取工作，但坚持给我没有事务性的EntityManager可用。为什么？ [英] Spring - JPA - Reads work but persist give me No transactional EntityManager available. Why?
本文介绍了Spring - JPA - 读取工作，但坚持给我没有事务性的EntityManager可用。为什么？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我正在用Spring和JPA构建一个应用程序。我的阅读功能正在工作，但当我尝试保存任何对象时，我收到了异常没有事务性的EntityManager可用。
这是我的网页。 xml文件：
<？xml version =1.0encoding =UTF-8？>
< web-app version =2.5xmlns =http://java.sun.com/xml/ns/javaee
xmlns：xsi =http：//www.w3。 org / 2001 / XMLSchema-instance
xsi：schemaLocation =http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web- app_2_5.xsd>
<！ - 所有Servlet共享的Root Spring容器的定义
和Filters - >
< context-param>
< param-name> contextConfigLocation< / param-name>
< param-value> /WEB-INF/spring/root-context.xml,/WEB-INF/spring/webservices-context.xml,/WEB-INF/spring/security-context.xml< / PARAM值>
< / context-param>
<！ - 创建所有Servlet和过滤器共享的Spring容器 - >
< listener>
< listener-class> org.springframework.web.context.ContextLoaderListener< / listener-class>
< / listener>
< filter>
< filter-name> springSecurityFilterChain< / filter-name>
< filter-class> org.springframework.web.filter.DelegatingFilterProxy< / filter-class>
< / filter>
< filter-mapping>
< filter-name> springSecurityFilterChain< / filter-name>
< url-pattern> / *< / url-pattern>
< / filter-mapping>
< mime-mapping>
< extension> js< / extension>
< mime-type> application / x-javascript< / mime-type>
< / mime-mapping>
< mime-mapping>
< extension>属性< / extension>
< mime-type> application / text< / mime-type>
< / mime-mapping>
<！ - 处理应用程序请求 - >
< servlet>
< servlet-name> appServlet< / servlet-name>
< servlet-class> org.springframework.web.servlet.DispatcherServlet< / servlet-class>
< init-param>
< param-name> contextConfigLocation< / param-name>
< param-value> /WEB-INF/spring/appServlet/servlet-context.xml< / param-value>
< / init-param>
1< / load-on-startup>
< / servlet>
< servlet-mapping>
< servlet-name> appServlet< / servlet-name>
< url-pattern> /< / url-pattern>
< / servlet-mapping>
< / web-app>
以下是我的spring / appServlet / servlet-context.xml：
<？xml version =1.0encoding =UTF-8？>
< beans：beans xmlns =http://www.springframework.org/schema/mvc
xmlns：xsi =http://www.w3.org/2001/XMLSchema-instance
xmlns：beans =http://www.springframework.org/schema/beans
xmlns：context =http://www.springframework.org/schema/context
xsi：schemaLocation =http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http：//www.springframework。 org / schema / beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org /schema/context/spring-context.xsd\">
<！ - DispatcherServlet上下文：定义这个servlet的请求处理基础结构 - >
<！ - 启用Spring MVC @Controller编程模型 - >
< annotation-driven />
< beans：bean id =placeholderConfigclass =org.springframework.beans.factory.config.PropertyPlaceholderConfigurer>
< beans：property name =locationvalue =classpath：resources.properties>< / beans：property>
< / beans：bean>
<！ - 通过高效地提供$ {webappRoot} / resources目录中的静态资源来处理/ resources / **的HTTP GET请求 - >
< resources mapping =/ **location =$ {resources.base}，$ {resources.modules}，$ {resources.lib}，$ {resources.apps}/> <！ - extjs和Designer的资源映射到/ - >
< resources mapping =/ resources / **location =$ {resources.resources}/>
<！ - 解析@Controllers为/ WEB-INF / views目录中的.jsp资源选择渲染的视图 - >
< beans：bean class =org.springframework.web.servlet.view.InternalResourceViewResolver>
< beans：property name =prefixvalue =/ WEB-INF / views //>
< beans：property name =suffixvalue =。jsp/>
< / beans：bean>
< context：component-scan base-package =com.app.webapp/>
< / beans：beans>
这是我的spring / root-context.xml：
<？xml version =1.0encoding =UTF-8standalone =no？>
< beans xmlns =http://www.springframework.org/schema/beans
xmlns：mvc =http://www.springframework.org/schema/mvc
xmlns：p =http://www.springframework.org/schema/pxmlns：tx =http://www.springframework.org/schema/tx
xmlns：context =http： //www.springframework.org/schema/context
xmlns：aop =http://www.springframework.org/schema/aop
xmlns：xsi =http：// www。 w3.org/2001/XMLSchema-instance
xsi：schemaLocation =http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/ spring-beans-3.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop-3.0.xsd
http：// www .springframework.org / schema / mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/context
http：//www.springframe work.org/schema/context/spring-context-3.0.xsd\">
<！ - 根上下文：定义对所有其他Web组件可见的共享资源 - >
< context：annotation-config />
< bean id =viewResolver
class =org.springframework.web.servlet.view.InternalResourceViewResolver>
< property name =prefixvalue =/ WEB-INF / views //>
< property name =suffixvalue =。jsp/>
< / bean>
class =org.springframework.jdbc.datasource.DriverManagerDataSource
p：driverClassName =com.mysql.jdbc.Driverp ：url =jdbc：mysql：// localhost / schema1
p：username =user1p：password =741147>
< / bean>
< bean id =entityManagerFactory
class =org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean>
< property name =dataSourceref =appDS/>
< property name =jpaVendorAdapter>
< bean class =org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter/>
< / property>
< / bean>
< bean id =transactionManagerclass =org.springframework.orm.jpa.JpaTransactionManager>
< property name =entityManagerFactoryref =entityManagerFactory/>
< / bean>
< tx：注解驱动的事务管理器=transactionManager/>
< bean id =persistenceExceptionTranslationPostProcessor
class =org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor/>
< context：spring-configured />
< context：annotation-config />
< / beans>
这是我的persistence.xml：
<？xml version =1.0encoding =UTF-8？>
< persistence version =2.0xmlns =http://java.sun.com/xml/ns/persistencexmlns：xsi =http://www.w3.org/2001/XMLSchema-实例xsi：schemaLocation =http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd\">
< persistence-unit name =myPUtransaction-type =JTA>
< provider> org.hibernate.ejb.HibernatePersistence< / provider>
<属性>
< property name =hibernate.dialectvalue =org.hibernate.dialect.MySQLDialect/>
< property name =hibernate.transaction.auto_close_sessionvalue =false/>
< property name =hibernate.show_sqlvalue =true/>
< property name =hibernate.format_sqlvalue =false/>
< property name =hibernate.generate_statisticsvalue =false/>
< property name =hibernate.connection.autocommitvalue =true/>
<！ - < property name =hibernate.hbm2ddl.autovalue =update/> - >
< property name =hibernate.query.jpaql_strict_compliancevalue =false/>
< property name =hibernate.transaction.jta.platformvalue =org.hibernate.service.jta.platform.internal.SunOneJtaPlatform/>
< property name =hibernate.connection.driver_classvalue =com.mysql.jdbc.Driver/>
< / properties>
< / persistence-unit>
< /余辉>
这是我的DaoImpl.java：
import java.util.ArrayList;
import java.util.HashSet;
import java.util.Iterator;
import java.util.List;
import java.util.Set;
导入javax.persistence.EntityManager;
import javax.persistence.PersistenceContext;
import javax.persistence.Query;
导入org.slf4j.Logger;
导入org.slf4j.LoggerFactory;
import org.springframework.stereotype.Repository;
import org.springframework.transaction.annotation.Propagation;
import org.springframework.transaction.annotation.Transactional;
import com.app.webapp.data.dao.impl.GenericDaoImpl;
import com.app.webapp.data.dao.interfaces.security.IUserDao;
import com.app.webapp.data.domains.entities.Account;
import com.app.webapp.data.domains.entities.security.AccessPrivilege;
import com.app.webapp.data.domains.entities.security.ActiveSession;
import com.app.webapp.data.domains.entities.security.Process;
import com.app.webapp.data.domains.entities.security.Profile;
import com.app.webapp.data.domains.entities.security.User;
import com.app.webapp.data.exceptions.DuplicatedUserException;
import com.app.webapp.data.exceptions.UserAlreadyHasAnAccountException;
import com.app.webapp.data.exceptions.UserNotFoundException;
@Repository（userDao）
@Transactional
public class UserDaoImpl implements IUserDao {
@PersistenceContext（unitName =myPU）
protected EntityManager entityManager;
public UserDaoImpl（）{
super（User.class）;
$ b @Override
@Transactional（readOnly = false，propagation = Propagation.REQUIRES_NEW）
public void save（User user）throws DuplicatedUserException {
logger.info（使用用户名创建用户名：+ user.getUsername（））;
User foundUser = null;
logger.info（检查用户是否已经存在...）;
entityManager.persist（user）;
logger.info（User+ user.getUsername（）+已成功保存！）;
$ b $ / code $ / pre
然后持续用户的行是
javax.persistence.TransactionRequiredException：没有事务性的EntityManager可用
但我不明白为什么我可以从数据库获取数据，但我无法写入。我不知道servlet上下文中是否有任何内容，并且不与其他上下文共享。有人可以帮助我吗？
解决方案您是否提供了 @Transactional 在 @Service 或服务层类？如果是，请检查您的 hibernet / entityManager.jar 版本兼容性。
I am building an application with spring and JPA. My read functions are working but when i try to save any objects, i get the exception No transactional EntityManager available.
Here is my web.xml file:
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<!-- The definition of the Root Spring Container shared by all Servlets
and Filters -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/root-context.xml,/WEB-INF/spring/webservices-context.xml,/WEB-INF/spring/security-context.xml</param-value>
</context-param>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<mime-mapping>
<extension>js</extension>
<mime-type>application/x-javascript</mime-type>
</mime-mapping>
<mime-mapping>
<extension>properties</extension>
<mime-type>application/text</mime-type>
</mime-mapping>
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
Here is my spring/appServlet/servlet-context.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->
<!-- Enables the Spring MVC @Controller programming model -->
<annotation-driven />
<beans:bean id="placeholderConfig" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<beans:property name="location" value="classpath:resources.properties"></beans:property>
</beans:bean>
<!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
<resources mapping="/**" location="${resources.base}, ${resources.modules}, ${resources.lib}, ${resources.apps}" /> <!-- resource mapp for extjs and Designer to / -->
<resources mapping="/resources/**" location="${resources.resources}" />
<!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory -->
<beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
</beans:bean>
<context:component-scan base-package="com.app.webapp" />
</beans:beans>
Here is my spring/root-context.xml:
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:p="http://www.springframework.org/schema/p" xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop-3.0.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<!-- Root Context: defines shared resources visible to all other web components -->
<context:annotation-config />
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/views/" />
<property name="suffix" value=".jsp" />
</bean>
<bean id="appDS"
class="org.springframework.jdbc.datasource.DriverManagerDataSource"
p:driverClassName="com.mysql.jdbc.Driver" p:url="jdbc:mysql://localhost/schema1"
p:username="user1" p:password="741147">
</bean>
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="appDS" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" />
</property>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
<tx:annotation-driven transaction-manager="transactionManager" />
<bean id="persistenceExceptionTranslationPostProcessor"
class="org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor" />
<context:spring-configured />
<context:annotation-config />
</beans>
Here is my persistence.xml:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="myPU" transaction-type="JTA">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect"/>
<property name="hibernate.transaction.auto_close_session" value="false"/>
<property name="hibernate.show_sql" value="true"/>
<property name="hibernate.format_sql" value="false"/>
<property name="hibernate.generate_statistics" value="false"/>
<property name="hibernate.connection.autocommit" value="true"/>
<!-- <property name="hibernate.hbm2ddl.auto" value="update"/> -->
<property name="hibernate.query.jpaql_strict_compliance" value="false"/>
<property name="hibernate.transaction.jta.platform" value="org.hibernate.service.jta.platform.internal.SunOneJtaPlatform" />
<property name="hibernate.connection.driver_class" value="com.mysql.jdbc.Driver"/>
</properties>
</persistence-unit>
</persistence>
Here is my DaoImpl.java:
import java.util.ArrayList;
import java.util.HashSet;
import java.util.Iterator;
import java.util.List;
import java.util.Set;
import javax.persistence.EntityManager;
import javax.persistence.PersistenceContext;
import javax.persistence.Query;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.stereotype.Repository;
import org.springframework.transaction.annotation.Propagation;
import org.springframework.transaction.annotation.Transactional;
import com.app.webapp.data.dao.impl.GenericDaoImpl;
import com.app.webapp.data.dao.interfaces.security.IUserDao;
import com.app.webapp.data.domains.entities.Account;
import com.app.webapp.data.domains.entities.security.AccessPrivilege;
import com.app.webapp.data.domains.entities.security.ActiveSession;
import com.app.webapp.data.domains.entities.security.Process;
import com.app.webapp.data.domains.entities.security.Profile;
import com.app.webapp.data.domains.entities.security.User;
import com.app.webapp.data.exceptions.DuplicatedUserException;
import com.app.webapp.data.exceptions.UserAlreadyHasAnAccountException;
import com.app.webapp.data.exceptions.UserNotFoundException;
@Repository("userDao")
@Transactional
public class UserDaoImpl implements IUserDao {
@PersistenceContext(unitName = "myPU")
protected EntityManager entityManager;
public UserDaoImpl() {
super(User.class);
}
@Override
@Transactional(readOnly = false, propagation = Propagation.REQUIRES_NEW)
public void save(User user) throws DuplicatedUserException {
logger.info("Creating User with username: " + user.getUsername());
User foundUser = null;
logger.info("Checking if user already existis...");
entityManager.persist(user);
logger.info("User " + user.getUsername() + " was been saved with success!");
}
}
Then the line to persist user is executed, I got the exception:
javax.persistence.TransactionRequiredException: No transactional EntityManager available
But I can't understand why I can get data from db but I cannot write. I don't know if is anything in the servlet context and isn't shared with others contexts. Someone can help me?
解决方案 Have you provide the @Transactional Annotation in @Service or service layer class? if yes then check your hibernet/entityManager.jar version compatibility.
这篇关于Spring - JPA - 读取工作，但坚持给我没有事务性的EntityManager可用。为什么？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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