许多到许多Hibernate映射与额外的列? [英] Many to many hibernate mapping with extra columns?
问题描述
你好,我有多对多的连接表中的额外列映射。
表结构看起来像这样。
表供应商{vendor_id,vendor_name,vendor_password等}
table student {student_id,student_name,student_password等}
table test {test_id,test_subject,test_price,test_level等。}
关系如下
vendor to test - >多对多
学生来测试 - >多对多
link
表vendor_student_test {vendor_id,student_id,test_id,purchasedDate,assignedDate,writtenDate,result}
我创建了POJO类如下:
$ b
- Vendor.java
公共类供应商{
Long vendorId;
Set< VendorStudentTest>测试;
//设定并获得
}
- Student.java
公开课学生{
Long studentId;
Set< VendorStudentTest>测试;
//设定并获得
}
- Test.java
public class Test {
Long test_id;
double test_price;
//设置并获取剩余字段
}
- VendorStudentTest.java
public class VendorStudentTest {
public VendorStudentTestPK vendorStudentTestPK;
日期购买日期;
日期assignDate;
日期书写日期;
双倍结果;
//设置并相应得到
}
<
public class VendorStudentTestPK {
Long vendor_id;
Long student_id;
Long test_id;
code $ <$ $ p
Hibernate映射文件如下
vendor.hbm.xml
< set name =tests表=vendor_student_test
inverse =truelazy =truefetch =select>
< key>
< column name =vendor_idnot-null =true/>
< / key>
<一对多等级=VendorStudentTest/>
< / set>
vendor_student_test.hbm.xml
< composite-id name =vendorStudentTestPK
class =com.onlineexam.model.VendorStudentTestPK>
< key-property name =vendorcolumn =vendor_id
type =java.lang.Long/>
type =java.lang.Long/>
< key-property name =testcolumn =test_idtype =java.lang.Long/>
< / composite-id>
student.hbm.xml
< set name =teststable =vendor_student_test
inverse =truelazy =truefetch =select>
< key>
< column name =student_idnot-null =true/>
< / key>
<一对多等级=VendorStudentTest/>
< / set>
test.hbm.xml
//这是映射到其他表
,这是否正确的映射?
解决方案与注释案例可以在这里找到
如何从连接表创建多个到多个Hibernate映射的附加属性?使用xml文件的解决方案可以在这里找到:
$ b a href =https://stackoverflow.com/questions/3813941/mapping-same-class-relation>映射相同的类关系
和这里:
Hi i have many to many mapping with extra columns in the join table. table structure look like this.
table vendor{vendor_id, vendor_name, vendor_password, etc...}
table student{student_id, student_name, student_password, etc..}
table test{test_id, test_subject, test_price,test_level, etc..}
Relations as follows
vendor to test --> many-to-many
student to test --> many-to-many
link
table vendor_student_test{vendor_id, student_id, test_id, purchasedDate, assignedDate, writtenDate, result}
i created POJO classes as follows
- Vendor.java
public class Vendor { Long vendorId; Set<VendorStudentTest> tests; //set and get }
- Student.java
public class Student{ Long studentId; Set<VendorStudentTest> tests; //set and get }
- Test.java
public class Test{ Long test_id; double test_price; //set and get and remaining fields }
- VendorStudentTest.java
public class VendorStudentTest{ public VendorStudentTestPK vendorStudentTestPK; Date purchasedDate; Date assignDate; Date writtenDate; double result; //set and get accordingly }
- VendorStudentTestPK.java
public class VendorStudentTestPK{ Long vendor_id; Long student_id; Long test_id; }
Hibernate mapping files as follows
vendor.hbm.xml
<set name="tests" table="vendor_student_test"
inverse="true" lazy="true" fetch="select">
<key>
<column name="vendor_id" not-null="true" />
</key>
<one-to-many class="VendorStudentTest" />
</set>
vendor_student_test.hbm.xml
<composite-id name="vendorStudentTestPK"
class="com.onlineexam.model.VendorStudentTestPK">
<key-property name="vendor" column="vendor_id"
type="java.lang.Long" />
<key-property name="student" column="student_id"
type="java.lang.Long" />
<key-property name="test" column="test_id" type="java.lang.Long" />
</composite-id>
student.hbm.xml
<set name="tests" table="vendor_student_test"
inverse="true" lazy="true" fetch="select">
<key>
<column name="student_id" not-null="true" />
</key>
<one-to-many class="VendorStudentTest" />
</set>
test.hbm.xml
//this is mapped to other table
I am new to hibernate, Is this correct mapping?
solution with Annotation Case can be found here
How Do I Create Many to Many Hibernate Mapping for Additional Property from the Join Table?
Solution using xml file can be found here: Mapping same class relation
and here:
Mapping same class relation - continuation
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