使用hibernate在一对多的映射中获得更新的行 [英] get updated row in one to many mapping using hibernate
问题描述
我有两个实体Issue和 Issue_Tracker
。我已经以一对多的方式加入了这张桌子。在 Issue_Tracker
中,我们可以有多个条目,如
issue_id tracker_status tracked_time
123分配2013/1/8 11:44
123分配2013/1/8 11:45
123已完成1 / 8/2013 11:52
32已分配2013/1/9 16:46
33已分配2013/1/9 16:47
33取消1/9/2013 16:49
我想通过tracked_time来订购Issue_tracker实体,这样我只能得到最后一次更新 tracker_status
。我使用条件来获取数据,但是我得到第一个条目,例如:对于issue_id 123,我将tracker_status设为Assigned,但是我想要获取 tracker_status:Completed
为id 123.如何实现这一点。我的DAO如下所示:
Criteria criteria = session.createCriteria(Issue.class);
criteria.setFirstResult(from);
criteria.setMaxResults(size);
criteria.setFetchMode(Issue.issueTracker,FetchMode.JOIN);
criteria.add(Restrictions.eq(status,Escalate To));
return criteria.list();
Issue.java
$ b $公共类的问题实现Serializable
{
私人整数issue_id;
private String issue_description;
私人日期issue_raised_date;
private Set< Issue_Tracker> issueTracker = new HashSet< Issue_Tracker>(0);
@OneToMany(fetch = FetchType.LAZY,mappedBy =issue_id)
public Set< Issue_Tracker> getIssueTracker(){
return issueTracker;
}
public void setIssueTracker(Set< Issue_Tracker> issueTracker){
this.issueTracker = issueTracker;
Issue_Tracker.java
$ b $公共类Issue_Tracker实现了Serializable
{
private Integer issue_id;
私人字符串tracker_status;
私人时间戳记tracked_time;
我希望你们能得到我想问的问题,有什么帮助吗? b $ b
将@OrderBy注释添加到映射集合中。这应该返回按跟踪时间排序的集合中的实体。
// Issue.java
@OneToMany(fetch = FetchType .LAZY,mappedBy =issue_id)
@OrderBy(tracked_time DESC)
public Set< Issue_Tracker> getIssueTracker(){
return issueTracker;
您可能还想尝试:
Criteria criteria = session.createCriteria(Issue.class);
criteria.setFirstResult(from);
criteria.setMaxResults(size);
criteria.setFetchMode(Issue.issueTracker,FetchMode.JOIN);
criteria.add(Restrictions.eq(status,Escalate To));
标准subCriteria = criteria.createCriteria(issueTracker);
subCriteria.addOrder(Order.desc(tracked_time));
return criteria.list();
I have two entities Issue and Issue_Tracker
. I have joined both table in an one to many mapping. In Issue_Tracker
, We can have multiple entries like
issue_id tracker_status tracked_time
123 Assigned 1/8/2013 11:44
123 Assigned 1/8/2013 11:45
123 Completed 1/8/2013 11:52
32 Assigned 1/9/2013 16:46
33 Assigned 1/9/2013 16:47
33 Cancel 1/9/2013 16:49
I want to Order the Issue_tracker entity by tracked_time so I can get only last update tracker_status
.I am using criteria to get data,However I am getting first entry for example : for issue_id 123, I get tracker_status as Assigned , But I want to fetch tracker_status : Completed
for id 123. How to achieve this. My DAO is as follows
Criteria criteria = session.createCriteria(Issue.class);
criteria.setFirstResult(from);
criteria.setMaxResults(size);
criteria.setFetchMode("Issue.issueTracker",FetchMode.JOIN);
criteria.add(Restrictions.eq("status", "Escalate To"));
return criteria.list();
Issue.java
public class Issue implements Serializable
{
private Integer issue_id;
private String issue_description;
private Date issue_raised_date;
private Set<Issue_Tracker> issueTracker = new HashSet<Issue_Tracker>(0);
@OneToMany(fetch=FetchType.LAZY, mappedBy="issue_id")
public Set<Issue_Tracker> getIssueTracker() {
return issueTracker;
}
public void setIssueTracker(Set<Issue_Tracker> issueTracker) {
this.issueTracker = issueTracker;
Issue_Tracker.java
public class Issue_Tracker implements Serializable
{
private Integer issue_id;
private String tracker_status;
private Timestamp tracked_time;
I hope you guys can get what i am trying to ask, any help?
Add an @OrderBy annotation to the mapped collection. This should return the entities in the set ordered by the tracked time. The first entity in the set should be the latest.
//Issue.java
@OneToMany(fetch=FetchType.LAZY, mappedBy="issue_id")
@OrderBy("tracked_time DESC")
public Set<Issue_Tracker> getIssueTracker() {
return issueTracker;
You may also want to try:
Criteria criteria = session.createCriteria(Issue.class);
criteria.setFirstResult(from);
criteria.setMaxResults(size);
criteria.setFetchMode("Issue.issueTracker",FetchMode.JOIN);
criteria.add(Restrictions.eq("status", "Escalate To"));
Criteria subCriteria = criteria.createCriteria("issueTracker");
subCriteria.addOrder(Order.desc("tracked_time"));
return criteria.list();
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