将简单的SQL查询转换为JPA ... OneToMany关系 [英] Convert simple SQL query to JPA... OneToMany Relationship
问题描述
我有一个JPA(Hibernate)模型...一个对象包含其他对象的列表。如果我想运行SQL查询来搜索BOTH对象,那么它相对比较简单,我做了一个LEFT JOIN,并在所有列上执行简单的 LIKE%searchString%
。
SELECT * FROM my_db.person LEFT JOIN my_db.record ON record.person_pk WHERE ....;
我无法将其转换为JPA样式查询..模型如下所示
@Access(AccessType.FIELD)
@Entity
@Table(name =person)
public class Person {
@Column(nullable = true)
private String name;
@Column(nullable = true)
私有字符串地址;
$ b $ @ @neToMany(cascade = {CascadeType.PERSIST,CascadeType.MERGE,CascadeType.REFRESH},mappedBy =debtor)
@LazyCollection(LazyCollectionOption.FALSE)
private List< ;记录> records = new LinkedList<>();
...
...
匹配ManyToOne
@Entity
@Table(name =record )
public class Record实现Serializable {
@ManyToOne(cascade = {CascadeType.PERSIST,CascadeType.MERGE,CascadeType.REFRESH})
@JoinColumn(name =person_pk )
私人人物;
@Column(nullable = true)
private String factor1;
@Column(nullable = true)
private String factor2;
我想做一个JPA样式的搜索,搜索Person对象中所有可用的列,相关/嵌入记录对象列表中的列。例如,如果searhString是tom,Person实体1的名称是tom,则将返回(包含所有嵌入的对象),并且如果Person的实体10对于ex,因子1的值为tom,则此Person对象也会被返回。
谢谢 从Person中选择distinct p p
left join fetch p.records r
其中p.name类似于:search
或r.factor1 like:search
在将其作为参数传递之前,您需要在搜索周围添加%字符。
I have a JPA (Hibernate) model...One object contains a List of other objects. If i want to run a SQL query to search BOTH objects it is relatively straightforward, I do a LEFT JOIN and do a simple LIKE %searchString%
on all columns.
SELECT * FROM my_db.person LEFT JOIN my_db.record ON record.person_pk WHERE .... ;
I cannot convert this to a JPA style query.. The model is like this
@Access(AccessType.FIELD)
@Entity
@Table(name = "person")
public class Person {
@Column(nullable = true)
private String name;
@Column(nullable = true)
private String address;
@OneToMany(cascade = {CascadeType.PERSIST, CascadeType.MERGE, CascadeType.REFRESH}, mappedBy="debtor")
@LazyCollection(LazyCollectionOption.FALSE)
private List<Record> records = new LinkedList<>();
...
...
The matching ManyToOne
@Entity
@Table(name = "record")
public class Record implements Serializable {
@ManyToOne(cascade = {CascadeType.PERSIST, CascadeType.MERGE, CascadeType.REFRESH})
@JoinColumn(name="person_pk")
private Person person;
@Column(nullable = true)
private String factor1;
@Column(nullable = true)
private String factor2;
I would like to do a JPA style search that searches all available columns in the Person object AND all available columns in the List of related/embedded Record objects. For example if the searhString was "tom" and Person entity 1 had a name of "tom" this would be returned(with all embedded objects) and if Person entity 10, for ex, had a value of "tom" for factor1 this Person object would also be returned.
Thanks
select distinct p from Person p
left join fetch p.records r
where p.name like :search
or r.factor1 like :search
You will need to add % characters around search before you pass it as a parameter.
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