我该如何从该脚本中获取脚本文件名？ [英] How might I get the script filename from within that script?

问题描述

如果我的网站引用了名为whatever.js的脚本，则是有可能从该脚本中获得whatever.js？像：

  var scriptName = ??? 
 $ b $ if（typeof jQuery！==function）{
 throw new Error（
jQuery的脚本需要在+ 
 scriptName +之前加载）。检查< script>标记顺序。）; 
} 
  

可能比依赖检查值得的更麻烦，但到底是什么。 / p>

解决方案

  var scripts = document.getElementsByTagName（'script'）; 
 var lastScript = scripts [scripts.length-1]; 
 var scriptName = lastScript.src; 
 alert（loading：+ scriptName）; 
  

测试：FF 3.0.8，Chrome 1.0.154.53，IE6

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另见：我如何引用加载当前执行脚本的脚本标记？

I'm pretty sure the answer is no, but thought I'd ask anyway.

If my site references a scripted named "whatever.js", is it possible to get "whatever.js" from within that script? Like:

var scriptName = ???

if (typeof jQuery !== "function") {
    throw new Error(
        "jQuery's script needs to be loaded before " + 
        scriptName + ". Check the <script> tag order.");
}

Probably more trouble than it's worth for dependency checking, but what the hell.

解决方案

var scripts = document.getElementsByTagName('script');
var lastScript = scripts[scripts.length-1];
var scriptName = lastScript.src;
alert("loading: " + scriptName);

Tested in: FF 3.0.8, Chrome 1.0.154.53, IE6

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See also: How may I reference the script tag that loaded the currently-executing script?

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