我该如何更改python脚本本身? [英] How can I make a python script change itself?

问题描述

如何更改python脚本本身?

How can I make a python script change itself?

要精简一下，我想要一个像这样的python脚本(run.py)

To boil it down, I would like to have a python script (run.py)like this

a = 0
b = 1
print a + b
# do something here such that the first line of this script reads a = 1

下次运行脚本时，它看起来像

Such that the next time the script is run it would look like

a = 1
b = 1
print a + b
# do something here such that the first line of this script reads a = 2

这有可能吗?该脚本可能使用外部资源.但是，只要运行一个run.py文件，一切都应该工作.

Is this in any way possible? The script might use external resources; however, everything should work by just running the one run.py-file.

可能还不够清楚，但是脚本应该更新自身，而不是其他文件.当然，一旦在脚本旁边允许一个简单的配置文件，此任务就变得微不足道了.

It may not have been clear enough, but the script should update itself, not any other file. Sure, once you allow for a simple configuration file next to the script, this task is trivial.

答案:

实际上比想象的要容易得多. @khelwood的建议效果很好，打开脚本并将其自己的内容写入其中完全没有问题. @Gerrat的解决方案也很好用.这就是我的想法:

It is actually much easier than thought. @khelwood 's suggestion works just fine, opening the script and writing it's own content to it is completely unproblematic. @Gerrat's solution also works nicely. This is how I'm having it:

# -*- coding: utf-8 -*-
a = 0
b = 1
print a + b

content = []
with open(__file__,"r") as f:
    for line in f:
        content.append(line)

with open(__file__,"w") as f:
    content[1] = "a = {n}\n".format(n=b)
    content[2] = "b = {n}\n".format(n=a+b)
    for i in range(len(content)):
        f.write(content[i])

推荐答案

例如(每次运行时更改a的值):

For an example (changing the value of a each time its run):

a = 0
b = 1
print a + b

with open(__file__, 'r') as f:
    lines = f.read().split('\n')
    val = int(lines[0].split(' = ')[-1])
    new_line = 'a = {}'.format(val+1)
    new_file = '\n'.join([new_line] + lines[1:])

with open(__file__, 'w') as f:
    f.write('\n'.join([new_line] + lines[1:]))

这篇关于我该如何更改python脚本本身?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！