如何从脚本本身中获取Bash脚本的源目录? [英] How to get the source directory of a Bash script from within the script itself?

问题描述

如何获取 Bash 脚本所在的目录的路径位于该脚本的内部?

How do I get the path of the directory in which a Bash script is located, inside that script?

我想使用Bash脚本作为另一个应用程序的启动器.我想将工作目录更改为Bash脚本所在的目录，以便可以对该目录中的文件进行操作，如下所示:

I want to use a Bash script as a launcher for another application. I want to change the working directory to the one where the Bash script is located, so I can operate on the files in that directory, like so:

$ ./application

推荐答案

#!/bin/bash

DIR="$( cd "$( dirname "${BASH_SOURCE[0]}" )" >/dev/null 2>&1 && pwd )"

是有用的单行代码，无论从何处调用脚本，它都会为您提供脚本的完整目录名称.

is a useful one-liner which will give you the full directory name of the script no matter where it is being called from.

只要用于查找脚本的路径的最后一个组成部分不是符号链接(目录链接都可以)，它将起作用.如果您还想解析到脚本本身的任何链接，则需要一个多行解决方案:

It will work as long as the last component of the path used to find the script is not a symlink (directory links are OK). If you also want to resolve any links to the script itself, you need a multi-line solution:

#!/bin/bash

SOURCE="${BASH_SOURCE[0]}"
while [ -h "$SOURCE" ]; do # resolve $SOURCE until the file is no longer a symlink
  DIR="$( cd -P "$( dirname "$SOURCE" )" >/dev/null 2>&1 && pwd )"
  SOURCE="$(readlink "$SOURCE")"
  [[ $SOURCE != /* ]] && SOURCE="$DIR/$SOURCE" # if $SOURCE was a relative symlink, we need to resolve it relative to the path where the symlink file was located
done
DIR="$( cd -P "$( dirname "$SOURCE" )" >/dev/null 2>&1 && pwd )"

最后一个将与别名，source，bash -c，符号链接等的任意组合一起使用.

This last one will work with any combination of aliases, source, bash -c, symlinks, etc.

注意:如果在运行此代码段之前cd到其他目录，则结果可能不正确！

Beware: if you cd to a different directory before running this snippet, the result may be incorrect!

此外，请注意 陷阱和stderr输出副作用，如果用户巧妙地覆盖了cd而不是将输出重定向到stderr(包括转义序列，例如在Mac上调用update_terminal_cwd >&2时).在cd命令的末尾添加>/dev/null 2>&1会同时考虑到这两种可能性.

Also, watch out for $CDPATH gotchas, and stderr output side effects if the user has smartly overridden cd to redirect output to stderr instead (including escape sequences, such as when calling update_terminal_cwd >&2 on Mac). Adding >/dev/null 2>&1 at the end of your cd command will take care of both possibilities.

要了解其工作原理，请尝试运行以下更详细的形式:

To understand how it works, try running this more verbose form:

#!/bin/bash

SOURCE="${BASH_SOURCE[0]}"
while [ -h "$SOURCE" ]; do # resolve $SOURCE until the file is no longer a symlink
  TARGET="$(readlink "$SOURCE")"
  if [[ $TARGET == /* ]]; then
    echo "SOURCE '$SOURCE' is an absolute symlink to '$TARGET'"
    SOURCE="$TARGET"
  else
    DIR="$( dirname "$SOURCE" )"
    echo "SOURCE '$SOURCE' is a relative symlink to '$TARGET' (relative to '$DIR')"
    SOURCE="$DIR/$TARGET" # if $SOURCE was a relative symlink, we need to resolve it relative to the path where the symlink file was located
  fi
done
echo "SOURCE is '$SOURCE'"
RDIR="$( dirname "$SOURCE" )"
DIR="$( cd -P "$( dirname "$SOURCE" )" >/dev/null 2>&1 && pwd )"
if [ "$DIR" != "$RDIR" ]; then
  echo "DIR '$RDIR' resolves to '$DIR'"
fi
echo "DIR is '$DIR'"

它将显示类似以下内容的

And it will print something like:

SOURCE './scriptdir.sh' is a relative symlink to 'sym2/scriptdir.sh' (relative to '.')
SOURCE is './sym2/scriptdir.sh'
DIR './sym2' resolves to '/home/ubuntu/dotfiles/fo fo/real/real1/real2'
DIR is '/home/ubuntu/dotfiles/fo fo/real/real1/real2'

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