如何发挥从原料/资产的文件夹的音频文件的本地/默认媒体播放器？ [英] How to play audio file from raw/assets folder on the native/default media player?
问题描述
我知道我可以在媒体播放器一样，播放MP3文件：
意向意图=新的意图（）;
intent.setAction（android.content.Intent.ACTION_VIEW）;
档案文件=新的文件（YOUR_SONG_URI）;
intent.setDataAndType（Uri.fromFile（文件），音频/ *）;
startActivity（意向）;
开放的音频= Uri.parse（android.resource：//com.audio.test/+ R.raw.audio1）;
Log.d（TAG，URI：+ audio.toString（））;
和
开放的音频= Uri.parse（android.resource：//com.audio.test/raw/audio）;
Log.d（TAG，URI：+ audio.toString（））;
这将输出预期的结果：
01-24 15：28：23.190：D / MyClass的（30234）：URI：android.resource：//com.audio.test/2131034112
01-24 15时29分13秒：D / MyClass的（30234）：URI：android.resource：//com.audio.test/raw/audio1
不过，这是行不通的。媒体播放器不启动。任何想法，为什么？
更新
我包括createChooser和而不是预期的名单的球员，我收到了找不到应用程序来执行此操作的消息。这是我的确切code：
公共无效playAudio（）{
意图viewMediaIntent =新意图（）;
viewMediaIntent.setAction（android.content.Intent.ACTION_VIEW）;
乌里音频= Uri.parse（android.resource：//com.audio.test/raw/+ R.raw.audio1）;
Log.d（TAG，URI：+ audio.toString（））;
viewMediaIntent.setDataAndType（音，视频/ *）;
viewMediaIntent.addFlags（Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_SINGLE_TOP）;
Log.d（TAG，启动）;
意图I = Intent.createChooser（viewMediaIntent，播放音乐）;
mGap.startActivity（ⅰ）;
Log.d（TAG，启动）;
}
更新2
感谢您@CommonsWare的解释。现在我明白为什么它不工作。但问题仍然存在，我可以实现我想要的吗？得到一个文件的URI存储在原始/资产文件夹的文件：//方案？
更新3
我找到了一种方法来做到这一点，虽然这不是它的工作原理是最好的。我只有3个文件，这不耽误执行的。我复制从RES /生到手机上的本地目录中的文件并从该文件中获取的URI。如何避免这一步骤的任何建议都AP preciated。
公共无效copyFileToDir（字符串AUDIOFILE）{
文件测试= Environment.getExternalStoragePublicDirectory（Environment.DIRECTORY_MUSIC +/+ AUDIOFILE +.MP3）;
如果（test.exists（））{
Toast.makeText（mGap，存在，Toast.LENGTH_SHORT）.show（）;
返回;
}
文件DEST = Environment.getExternalStoragePublicDirectory（Environment.DIRECTORY_MUSIC）;
INT I = mGap.getResources（）则getIdentifier（原始/+的AudioFile，弦，mGap.getPackageName（））。
InputStream的时间= mGap.getResources（）openRawResource（我）。
//使用的文件，构造
的OutputStream出来;
尝试 {
OUT =新的FileOutputStream（新文件（DEST，AUDIOFILE +.MP3））;
//传输的字节从以出
byte []的BUF =新的字节[1024];
INT LEN;
尝试 {
//有一点更加明确
而（（LEN = in.read（buf中，0，buf.length））！= - 1）{
out.write（BUF，0，的len）;
}
} 最后 {
//确保流被关闭：
附寄（）;
out.close（）;
}
}赶上（FileNotFoundException异常E）{
// TODO自动生成的catch块
e.printStackTrace（）;
}赶上（IOException异常E）{
// TODO自动生成的catch块
e.printStackTrace（）;
}
}
公共无效playAudio（字符串AUDIOFILE）{
copyFileToDir（AUDIOFILE）;
文件DEST = Environment.getExternalStoragePublicDirectory（Environment.DIRECTORY_MUSIC +/+ AUDIOFILE +.MP3）;
乌里R = Uri.fromFile（DEST）;
意图viewMediaIntent =新意图（）;
viewMediaIntent.setAction（android.content.Intent.ACTION_VIEW）;
viewMediaIntent.setDataAndType（R，音频/ *）;
viewMediaIntent.addFlags（Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_SINGLE_TOP）;
意图I = Intent.createChooser（viewMediaIntent，播放音乐）;
mGap.startActivity（ⅰ）;
}
公共无效的playVideo（字符串movieurl）{
意图intentToPlayVideo =新的意图（Intent.ACTION_VIEW）;
intentToPlayVideo.setDataAndType（Uri.parse（movieurl），视频/ *）;
Log.d（TAG，饰演：+ movieurl）;
mGap.startActivity（intentToPlayVideo）;
}
当你调用 startActivity（），你想开始一个活动。该意图传递给 startActivity（）表示什么活动 - 或者选择了一组可用的活动中 - 要启动。在你的情况，您要查看 android.resource：// 乌里。这不是一个的http：// 乌里，也不是的https：// 乌里，也不是文件：// 乌里。
这是宣传自己配套的操作类似这样的有，在他们的＆LT活动;意向滤光器＆gt; 的说明是什么乌里方案所支持。你是假设有一个应用程序，用户的设备上，支持的 android.resource：// 方案。就个人而言，我不认为这是一个安全的假设。
的http：// ，的https：// 和文件：// 应该是安全的，而内容：// （对于的ContentProvider ）是相当有可能为好。
例如，在AOSP音乐应用程序不支持 android.resource 方案的基础上的当前清单内容的。
I know i can play an mp3 file in the media player like that:
Intent intent = new Intent();
intent.setAction(android.content.Intent.ACTION_VIEW);
File file = new File(YOUR_SONG_URI);
intent.setDataAndType(Uri.fromFile(file), "audio/*");
startActivity(intent);
Following this link I tried to get the URI like:
Uri audio = Uri.parse("android.resource://com.audio.test/"+R.raw.audio1);
Log.d(TAG,"uri:"+audio.toString());
and
Uri audio = Uri.parse("android.resource://com.audio.test/raw/audio");
Log.d(TAG,"uri:"+audio.toString());
Which outputs the expected result:
01-24 15:28:23.190: D/MyClass(30234): uri:android.resource://com.audio.test/2131034112
01-24 15:29:13.: D/MyClass(30234): uri:android.resource://com.audio.test/raw/audio1
But it doesn't work. The media player does not start. Any ideas why?
Update
I included a createChooser and instead of the expected list with players i get a "Unable to find application to perform this action" message. This is my exact code:
public void playAudio(){
Intent viewMediaIntent = new Intent();
viewMediaIntent.setAction(android.content.Intent.ACTION_VIEW);
Uri audio = Uri.parse("android.resource://com.audio.test/raw/"+R.raw.audio1);
Log.d(TAG,"uri:"+audio.toString());
viewMediaIntent.setDataAndType(audio, "video/*");
viewMediaIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_SINGLE_TOP);
Log.d(TAG,"Starting");
Intent i = Intent.createChooser(viewMediaIntent, "Play Music");
mGap.startActivity(i);
Log.d(TAG,"Started");
}
Update 2
Thank you @CommonsWare for the explanation. Now I understand why it doesn't work. But the problem remains, can I achieve what I want? Get a Uri of a file stored in the raw/assets folder with a file:// scheme?
Update 3
I found a way to do it, although it's not the best it works. I have only 3 files and this doesn't delay the execution at all. I am copying the file from the res/raw to a local directory on the phone and getting the Uri from that file. Any suggestions on how to avoid that step are appreciated.
public void copyFileToDir(String audioFile){
File test = Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_MUSIC + "/" + audioFile + ".mp3");
if (test.exists()){
Toast.makeText(mGap, "Exists", Toast.LENGTH_SHORT).show();
return;
}
File dest = Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_MUSIC);
int i = mGap.getResources().getIdentifier("raw/"+audioFile, "string", mGap.getPackageName());
InputStream in = mGap.getResources().openRawResource(i);
// Used the File-constructor
OutputStream out;
try {
out = new FileOutputStream(new File(dest, audioFile + ".mp3"));
// Transfer bytes from in to out
byte[] buf = new byte[1024];
int len;
try {
// A little more explicit
while ( (len = in.read(buf, 0, buf.length)) != -1){
out.write(buf, 0, len);
}
} finally {
// Ensure the Streams are closed:
in.close();
out.close();
}
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public void playAudio(String audioFile){
copyFileToDir(audioFile);
File dest = Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_MUSIC + "/" + audioFile + ".mp3");
Uri r = Uri.fromFile(dest);
Intent viewMediaIntent = new Intent();
viewMediaIntent.setAction(android.content.Intent.ACTION_VIEW);
viewMediaIntent.setDataAndType(r, "audio/*");
viewMediaIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_SINGLE_TOP);
Intent i = Intent.createChooser(viewMediaIntent, "Play Music");
mGap.startActivity(i);
}
public void playVideo(String movieurl){
Intent intentToPlayVideo = new Intent(Intent.ACTION_VIEW);
intentToPlayVideo.setDataAndType(Uri.parse(movieurl), "video/*");
Log.d(TAG,"Playing:" + movieurl);
mGap.startActivity(intentToPlayVideo);
}
When you call startActivity(), you are trying to start an activity. The Intent you pass to startActivity() indicates what activity -- or selection out of a set of available activities -- you want to start. In your case, you are trying to view an android.resource:// Uri. This is not an http:// Uri, nor an https:// Uri, nor a file:// Uri.
Activities that advertise themselves as supporting operations like this have, in their <intent-filter> a statement of what Uri schemes they support. You are assuming that there is an app, on the user's device, that supports an android.resource:// scheme. Personally, I do not think that this is a safe assumption.
http://, https://, and file:// should be safe, and content:// (for a ContentProvider) is fairly likely as well.
For example, the AOSP Music app does not support the android.resource scheme, based on its current manifest contents.
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