android从资产文件夹共享音频文件 [英] android share audio file from assets folder
问题描述
我无法从资产分享音频文件。
每个应用都表示无法发送文件。
将inputstream转换为临时文件的方法
public File getFile（String Prefix，String Suffix）throws IOException {
File tempFile = File.createTempFile（Prefix，Suffix）;
AssetFileDescriptor tempafd = FXActivity.getInstance（）。getAssets（）。openFd（filepath）;
tempFile.deleteOnExit（）;
FileOutputStream out = new FileOutputStream（tempFile）;
IOUtils.copy（tempafd.createInputStream（），out）;
return tempFile;
}
共享文件
item2.setOnAction（n - > {
try {
Uri uri = Uri.fromFile（tekst.getFile（tekst.getFilename（），.mp3 ））;
Intent share = new Intent（）;
share.setType（audio / *）;
share.setAction（Intent.ACTION_SEND）;
share.putExtra （Intent.EXTRA_STREAM，uri）;
FXActivity.getInstance（）。startActivity（share）;
} catch（IOException ex）{
Logger.getLogger（MainCategoryCreator.class.getName（）） .log（Level.SEVERE，null，ex）;
}
}）;
正如它发生的那样，我挣扎着几乎相同的问题：我需要分享视频文件。问题是：现在有共享内部文件的方法。决不。
您可能需要一个 ContentProvider ，或者因为它稍微简单一些，它的扩展名是 FileProvider 。
首先：您需要更新 AndroidManifest.xml ：
< provider
android：name =android.support.v4.content.FileProvider
android：authorities =my.package.fileprovider
android：exported =false
android：grantUriPermissions =true>
< meta-data
android：name =android.support.FILE_PROVIDER_PATHS
android：resource =@ xml / file_paths/>
< / provider>
这需要添加到 然后，您需要Android子目录<$中的XML文件< application>
file_paths.xml c $ c> res / xml /
它应该是这样的：
<路径xmlns：android =http://schemas.android.com/apk/res/android>
< files-path name =objectspath =objects //>
< /路径>
最后触发它，我需要像这样调用它：
Uri uri = Uri.parse（content：//my.package.fileprovider/+ fn）;
Intent intent = new Intent（Intent.ACTION_VIEW，uri）; //或每次解析uri
intent.setDataAndType（uri，video / *）; //所有视频类型== * - 替代品：mp4，...
intent.addFlags（Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_SINGLE_TOP | Intent.FLAG_GRANT_READ_URI_PERMISSION）;
列表< ResolveInfo> resInfoList = FXActivity.getInstance（）。getPackageManager（）。queryIntentActivities（intent，PackageManager.MATCH_DEFAULT_ONLY）;
for（ResolveInfo resolveInfo：resInfoList）{
String packageName = resolveInfo.activityInfo.packageName;
FXActivity.getInstance（）。grantUriPermission（packageName，uri，Intent.FLAG_GRANT_READ_URI_PERMISSION）;
}
FXActivity.getInstance（）。startActivity（intent）;
但是我之前需要做的事情是能够像这样使用它：我需要复制所有资产到私人文件目录，因为 请参阅 FileProvider上的Android Developer参考资料。我的简单解决方案如下所示： FileProvider 本身没有选项来访问你的资产（我想你可以用自定义 ContentProvider code>，但我找到了复杂的方法，并没有那么多时间）。
public boolean copyAssetsToStorage（）throws NativeServiceException {
try {
String [] assets = getContext（）。getAssets（）。list（DIR_NAME）;
if（assets == null || assets.length == 0）{
LOG.warning（没有在''中找到资产+ DIR_NAME +'！）;
返回false;
}
File filesDir = getContext（）。getFilesDir（）;
文件targetDir =新文件（filesDir，DIR_NAME）;
if（！targetDir.isDirectory（））{
boolean b = targetDir.mkdir（）;
if（！b）{
LOG.warning（无法使用名称+ DIR_NAME +'！创建私人目录）;
返回false;
for（String asset：assets）{
File targetFile = new File（targetDir，asset）;
if（targetFile.isFile（））{
LOG.info（Asset+ asset +already exists，Nothing to do。）;
继续;
} else {
LOG.info（将资产复制+资产+转换为私人文件。）;
}
InputStream is = null;
OutputStream os = null;
尝试{
is = getContext（）。getAssets（）。open（DIR_NAME +/+ asset）;
os = new FileOutputStream（targetFile.getAbsolutePath（））;
byte [] buff = new byte [1024];
int len; （（len = is.read（buff））> 0）
os.write（buff，0，len）;
} catch（IOException e）{
LOG.log（Level.SEVERE，e.getMessage（），e）;
继续;
}
if（os！= null）{
os.flush（）;
os.close（）;
}
if（is！= null）
is.close（）;
}
返回true;
} catch（IOException e）{
LOG.log（Level.SEVERE，e.getMessage（），e）;
返回false;
$ b你可以看到，我只支持一个扁平的层次结构现在......
这至少对我有用。
问候，
Daniel
附加问题 ：为什么要发送意图而不是实现一个简单的JavaFX音频播放器控件？这是我在视频内容之前所做的。
I can't share audio file from assets. Each app says that it can't send the file.
Method for converting inputstream to temporary file
public File getFile(String Prefix, String Suffix) throws IOException {
File tempFile = File.createTempFile(Prefix, Suffix);
AssetFileDescriptor tempafd = FXActivity.getInstance().getAssets().openFd(filepath);
tempFile.deleteOnExit();
FileOutputStream out = new FileOutputStream(tempFile);
IOUtils.copy(tempafd.createInputStream(), out);
return tempFile;
}
Sharing file
item2.setOnAction(n ->{
try {
Uri uri = Uri.fromFile(tekst.getFile(tekst.getFilename(), ".mp3"));
Intent share = new Intent();
share.setType("audio/*");
share.setAction(Intent.ACTION_SEND);
share.putExtra(Intent.EXTRA_STREAM, uri);
FXActivity.getInstance().startActivity(share);
} catch (IOException ex) {
Logger.getLogger(MainCategoryCreator.class.getName()).log(Level.SEVERE, null, ex);
}
});
Just as it happens, I struggled with almost an identical problem: I needed to share a video file. The problem is: There is now way to share an internal file. Never.
You either need a ContentProvider, or since it's a bit simpler with it, it's extension FileProvider.
First: you need to update you AndroidManifest.xml:
<provider
android:name="android.support.v4.content.FileProvider"
android:authorities="my.package.fileprovider"
android:exported="false"
android:grantUriPermissions="true">
<meta-data
android:name="android.support.FILE_PROVIDER_PATHS"
android:resource="@xml/file_paths" />
</provider>
This needs to be added into the <application>tag.
Then you need the XML file file_paths.xml in the Android sub-directory res/xml/
It should something like this:
<paths xmlns:android="http://schemas.android.com/apk/res/android">
<files-path name="objects" path="objects/"/>
</paths>
And to finally trigger it, I needed to call it like this:
Uri uri = Uri.parse("content://my.package.fileprovider/" + fn);
Intent intent = new Intent(Intent.ACTION_VIEW, uri); // or parse uri each time
intent.setDataAndType(uri, "video/*"); // all video type == * - alternative: mp4, ...
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_SINGLE_TOP | Intent.FLAG_GRANT_READ_URI_PERMISSION);
List<ResolveInfo> resInfoList = FXActivity.getInstance().getPackageManager().queryIntentActivities(intent, PackageManager.MATCH_DEFAULT_ONLY);
for (ResolveInfo resolveInfo : resInfoList) {
String packageName = resolveInfo.activityInfo.packageName;
FXActivity.getInstance().grantUriPermission(packageName, uri, Intent.FLAG_GRANT_READ_URI_PERMISSION);
}
FXActivity.getInstance().startActivity(intent);
But what I needed to do prior to be able to use it like this: I needed to copy all assets to the private files dir, because the FileProvider itself has no option to access your assets (I guess you could achieve this with a custom ContentProvider, but I found way to complicated and didn't have that much time).
See this Android Developer reference on FileProvider for mor information.
My simple solution for this looks like this:
public boolean copyAssetsToStorage() throws NativeServiceException {
try {
String[] assets = getContext().getAssets().list(DIR_NAME);
if (assets == null || assets.length == 0) {
LOG.warning("No assets found in '" + DIR_NAME + "'!");
return false;
}
File filesDir = getContext().getFilesDir();
File targetDir = new File(filesDir, DIR_NAME);
if (!targetDir.isDirectory()) {
boolean b = targetDir.mkdir();
if (!b) {
LOG.warning("could not create private directory with the name '" + DIR_NAME + "'!");
return false;
}
}
for (String asset : assets) {
File targetFile = new File(targetDir, asset);
if (targetFile.isFile()) {
LOG.info("Asset " + asset + " already present. Nothing to do.");
continue;
} else {
LOG.info("Copying asset " + asset + " to private files.");
}
InputStream is = null;
OutputStream os = null;
try {
is = getContext().getAssets().open(DIR_NAME + "/" + asset);
os = new FileOutputStream(targetFile.getAbsolutePath());
byte[] buff = new byte[1024];
int len;
while ((len = is.read(buff)) > 0)
os.write(buff, 0, len);
} catch (IOException e) {
LOG.log(Level.SEVERE, e.getMessage(), e);
continue;
}
if (os != null) {
os.flush();
os.close();
}
if (is != null)
is.close();
}
return true;
} catch (IOException e) {
LOG.log(Level.SEVERE, e.getMessage(), e);
return false;
}
}
As you can see, I only support a flat hierarchy for now...
This at least did the trick for me.
Regards, Daniel
ADDIDIONAL QUESTION: Why are you sending an Intent and not implement a simple JavaFX audio player control? This is what I did prior to the Video stuff.
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