发起呼叫在Android上使用特殊字符＃ [英] initiate a phone call on android with special character #

问题描述

我用下面的code从内部的Andr​​oid应用程序发起呼叫：

I use the following code to launch a call from within the android app:

intent.setData(Uri.parse("tel:+12345 #123"));
startActivity(intent);

虽然它开始通话，却忽视了一切开始的＃。

While it starts the call, it ignores everything starting with the #.

我读一些有关修改SpecialCharSequenceMgr.java文件，但我找不到这个任何地方，老实说不知道究竟一个人做。什么是解决这个问题的最好方法是什么？

I read something about modifying SpecialCharSequenceMgr.java file, but I can't find this anywhere and quite honestly don't know what exactly one has to do. What is the best way to solve this?

推荐答案

我相信这个问题是该＃符号在URI的一个特殊的意义，所以你使用<$ C $必须连接code这C> Uri.en code（）的方法是这样的：

I believe the problem is the that the # symbol has a special meaning in URIs, so you have to encode it using the Uri.encode() method like this:

    Intent out = new Intent();
    out.setAction(Intent.ACTION_DIAL);
    out.setData(Uri.parse("tel:" + Uri.encode("+12345#123")));
    startActivity(out);

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