如何根据他们的ID对LI进行排序 [英] How to sort LI's based on their ID
本文介绍了如何根据他们的ID对LI进行排序的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
<!DOCTYPE html>
< html>
< head>
< / head>
< body>
< ul id =dumb>
< li>大提琴< span> 2987< / span>< / li>
< li> zello< span> 1723< / span>< / li>
< li> aello< span> 3476< / span>< / li>
< / ul>
< script type ='text / javascript'src ='JQUERY INCLUDE'>< / script>
< script type =text / javascript>
$(document).ready(function(){
$('ul li span')。each(function(){
var pubValue = $(this).html();
$(this).parent()。attr('id',pubValue);
});
});
< / script>
< / body>
< / html>
解决方案
假设您的 li节点
有ID。
< ul id =test>
< li id =4112> blub< / li>
< li id =1422> blaaah< / li>
< li id =6640> hmmmm< / li>
< li id =2221>多一个< / li>
< / ul>
然后你可以调用javascripts native array .sort()
方法,因为jQuery包装集保存在数组中
:
<$ c $ ($())$($)$()函数(){
var elems = $('#test')。children('li')。remove();
elems.sort(function(a,b){
return parseInt(a.id)> parseInt(b.id);
});
$('#test')。append(elems);
});
工作示例: http://www.jsfiddle.net/3uYUq/
Trying a bunch of solutions with no workable results. I have code that takes the value of the span and creates an ID for the LI. I then want to sort these LI's DESCENDING based on the LI's ID. Help? Thanks!
<!DOCTYPE html>
<html>
<head>
</head>
<body>
<ul id="dumb">
<li>cello<span>2987</span></li>
<li>zello<span>1723</span></li>
<li>aello<span>3476</span></li>
</ul>
<script type='text/javascript' src='JQUERY INCLUDE'></script>
<script type="text/javascript">
$(document).ready(function() {
$('ul li span').each(function(){
var pubValue = $(this).html();
$(this).parent().attr('id', pubValue);
});
});
</script>
</body>
</html>
解决方案
Let's assume your li nodes
had ids.
<ul id="test">
<li id="4112">blub</li>
<li id="1422">blaaah</li>
<li id="6640">hmmmm</li>
<li id="2221">one more</li>
</ul>
Then you could just call javascripts native array .sort()
method, since jQuery wrapped sets are hold in Arrays
:
$(function(){
var elems = $('#test').children('li').remove();
elems.sort(function(a,b){
return parseInt(a.id) > parseInt(b.id);
});
$('#test').append(elems);
});
Working example: http://www.jsfiddle.net/3uYUq/
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