如何在localStorage上增加一个值 [英] How to increment a value at localStorage

问题描述

我有一些动态存储在localStorage的值，像这样递增的值：localStorage [Value0]，localStorage [Value1]，....

I have some values that are dynamically stored at localStorage with incremented values like this: localStorage["Value0"], localStorage["Value1"],....

当我尝试像这样访问它们时：

When I try to access them like this:

JavaScript：

JavaScript:

localStorage["Counter"]=0;
var i = localStorage["Counter"]; 
var d =localStorage["Value"+i];
i = i + 1; // i becomes "01"
var f = localStorage["Value"+i];

我的值是01而不是1 ...有没有办法增加i的值是否正确？

The i's value is "01" not 1 ... Is there a way to increment the i's value correctly?

推荐答案

LocalStorage只能存储字符串值。您可以使用parseInt将字符串转换为整数：

LocalStorage can only store string values. You can use parseInt which converts a string into an integer:

var new_value =  parseInt(localStorage.getItem('num')) + 1

您也可以使用像store.js这样的库为您自动执行操作。您只需包含该库：

You can also use libraries like store.js to do things automatically for you. All you have to do is to include the library:

<script src="store.js"></script>

设置新的存储空间：

var numbers = new Store("numbers")

它：

Put things into it:

numbers.set('num', 2)

获取价值并用它做任何事情：

Get the value and do anything you want with it:

numbers.get('num') + 1 //output: 3

你也可以发疯并使用一些数组：

And you can also go crazy and use some arrays:

numbers.set('nums', [1,2,3])

改变里面的东西：

And change things inside it:

numbers.get('nums')[0] + 3 //output: 4

不需要类型转换。你也可以存储对象，布尔值和其他东西。不要忘记将东西存回存储器，因为它不会自动执行。

No type conversion needed. You can also store objects, booleans and other stuff. Just don't forget to save things back in the storage since it doesn't automatically do it.

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