在html表中转置/交换x,y轴 [英] transpose/swap x,y axes in html table
本文介绍了在html表中转置/交换x,y轴的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个需要旋转/换轴的html表格。它可以离线完成。任何人都知道我可以用来做这件事的工具吗?
: p> < xsl:stylesheet version =1.0
xmlns:xsl =http://www.w3.org / 1999 / XSL /变换>
< xsl:output omit-xml-declaration =yes/>
< xsl:template match =table>
< xsl:for-each select =tr [1] / td>
< xsl:variable name =vRowPosselect =position()/>
< tr>
< xsl:for-each select =/ table / tr>
< xsl:variable name =vColPosselect =position()/>
< xsl:copy-of select =/ table / tr [$ vColPos] / td [$ vRowPos]/>
< / xsl:for-each>
< / tr>
< / xsl:for-each>
< / xsl:template>
< / xsl:stylesheet>
应用于此XML文档:
< table>
< tr>
< td> A11< / td>
< td> A12< / td>
< td> A13< / td>
< td> A14< / td>
< td> A15< / td>
< / tr>
< tr>
< td> A21< / td>
< td> A22< / td>
< td> A23< / td>
< td> A24< / td>
< td> A25< / td>
< / tr>
< tr>
< td> A31< / td>
< td> A32< / td>
< td> A33< / td>
< td> A34< / td>
< td> A35< / td>
< / tr>
< / table>
产生想要的正确结果
: < table>
< tr>
< td> A11< / td>
< td> A21< / td>
< td> A31< / td>
< / tr>
< tr>
< td> A12< / td>
< td> A22< / td>
< td> A32< / td>
< / tr>
< tr>
< td> A13< / td>
< td> A23< / td>
< td> A33< / td>
< / tr>
< tr>
< td> A14< / td>
< td> A24< / td>
< td> A34< / td>
< / tr>
< tr>
< td> A15< / td>
< td> A25< / td>
< td> A35< / td>
< / tr>
< / table>
请注意:假设表格具有常规结构。
I have an html table that needs rotating / axis swaping. It can be done off line. Any one know of a tool I can use to do it?
解决方案
This transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes"/>
<xsl:template match="table">
<xsl:for-each select="tr[1]/td">
<xsl:variable name="vRowPos" select="position()"/>
<tr>
<xsl:for-each select="/table/tr">
<xsl:variable name="vColPos" select="position()"/>
<xsl:copy-of select="/table/tr[$vColPos]/td[$vRowPos]"/>
</xsl:for-each>
</tr>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
when applied on this XML document:
<table>
<tr>
<td>A11</td>
<td>A12</td>
<td>A13</td>
<td>A14</td>
<td>A15</td>
</tr>
<tr>
<td>A21</td>
<td>A22</td>
<td>A23</td>
<td>A24</td>
<td>A25</td>
</tr>
<tr>
<td>A31</td>
<td>A32</td>
<td>A33</td>
<td>A34</td>
<td>A35</td>
</tr>
</table>
produces the wanted, correct results:
<table>
<tr>
<td>A11</td>
<td>A21</td>
<td>A31</td>
</tr>
<tr>
<td>A12</td>
<td>A22</td>
<td>A32</td>
</tr>
<tr>
<td>A13</td>
<td>A23</td>
<td>A33</td>
</tr>
<tr>
<td>A14</td>
<td>A24</td>
<td>A34</td>
</tr>
<tr>
<td>A15</td>
<td>A25</td>
<td>A35</td>
</tr>
</table>
Do note: The assumption is that the table has regular structure.
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