XPath：一起选择自己和兄弟姐妹 [英] XPath: Select self and following sibling together

问题描述

 < DIV> 
< dt> 
测试1 
< / dt> 
< dd> 
< / dd> 
< dt> 
测试2 
< / dt> 
< dd> 
< / dd> 
< / div> 
  

到目前为止我写了这个XPath

 // dt [contains（text（），Test）] / self :: dt | following-sibling :: dd 
  

但是，这并不是带来 dt 和 dd ，而是 dt 。

解决方案

如果它必须是单个XPath 1.0表达式，那么您必须说

  // dt [contains（。，'Test'）] | // dt [contains（。，'Test'）] / following-sibling :: dd [1] 
  

<最后的 [1] 非常重要，因为它不会提取包含Test的dt之后的所有 em元素，即给定

 < div> 
< dt> 
测试1 
< / dt> 
< dd> 
 Foo 
< / dd> 
< dt> 
其他2 
< / dt> 
< dd> 
 Bar 
< / dd> 
< / div> 
  

没有 [1] 的版本会匹配三个节点，包含测试1和em的 dt Foo和Bar dd code>元素。 [1] 您只能正确地获得Test 1和Foo。

但是，根据您使用XPath的具体情况，首先选择

  // dt [contains（。，'Test'）] 
  

然后遍历节点匹配，并评估

 。 |在每个这些节点的上下文中依次 -  sibling :: dd [1] 
  

。 / p>

<div>
    <dt>
        Test 1
    </dt>
    <dd>
    </dd>
    <dt>
        Test 2
    </dt>
    <dd>
    </dd>
</div>

I have this XPath written so far

//dt[contains(text(), "Test")]/self::dt|following-sibling::dd

But this is not bringing both dt and dd but just dt.

解决方案

If it must be a single XPath 1.0 expression then you'll have to say

//dt[contains(., 'Test')] | //dt[contains(., 'Test')]/following-sibling::dd[1]

The final [1] is important, as without that it would extract all dd elements that follow a dt containing "Test", i.e. given

<div>
    <dt>
        Test 1
    </dt>
    <dd>
        Foo
    </dd>
    <dt>
        Something else 2
    </dt>
    <dd>
        Bar
    </dd>
</div>

the version without the [1] would match three nodes, the dt containing "Test 1" and both the "Foo" and "Bar" dd elements. With the [1] you would correctly get only "Test 1" and "Foo".

But depending on exactly how you're using the XPath it may be clearer to first select

//dt[contains(., 'Test')]

and then iterate over the nodes that this matches, and evaluate

. | following-sibling::dd[1]

in the context of each of those nodes in turn.

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