如何在PHP中使用Regex提取HTML内容 [英] How do I extract HTML content using Regex in PHP
问题描述
我知道，我知道...正则表达式不是提取HTML文本的最佳方法。但我需要从很多页面中提取文章文本，我可以在每个网站的数据库中存储正则表达式。我不确定XML解析器如何与多个网站一起工作。每个网站都需要一个单独的功能。
在任何情况下，我对正则表达式都不太了解，请耐心等待。
我有一个类似于此格式的HTML页面
< html>
< head> ...< / head>
< body>
< div class = nav> ...< / div>< p id =someshit/>
< div class = body> ....< / div>
< div class = footer> ...< / div>
< / body>
我需要提取body类容器的内容。
我试过了。
$ pattern =/< div class = \body \ > \（。*？\）< \ / div> / sui
$ text = $ htmlPageAsIs;
if（preg_match（$ pattern，$ text，$ matches））
echoMATCHED！;
else
回声对不起gambooka，但你的文字在另一座城堡。;
我做错了什么？我的文本最终在另一座城堡。
*编辑：ooohh ...没关系，我发现可读性的代码
<您正在匹配 class =body您的文档有 class = body ：您错过了引号。使用/< div class = \？body \？>>（。*？）< \ / div> / sui p>
I know, i know... regex is not the best way to extract HTML text. But I need to extract article text from a lot of pages, I can store regexes in the database for each website. I'm not sure how XML parsers would work with multiple websites. You'd need a separate function for each website.
In any case, I don't know much about regexes, so bear with me.
I've got an HTML page in a format similar to this
<html>
<head>...</head>
<body>
<div class=nav>...</div><p id="someshit" />
<div class=body>....</div>
<div class=footer>...</div>
</body>
I need to extract the contents of the body class container.
I tried this.
$pattern = "/<div class=\"body\">\(.*?\)<\/div>/sui"
$text = $htmlPageAsIs;
if (preg_match($pattern, $text, $matches))
echo "MATCHED!";
else
echo "Sorry gambooka, but your text is in another castle.";
What am I doing wrong? My text ends up in another castle.
*EDIT: ooohh... never mind, I found readability's code
You are matching for class="body" your document has class=body: you're missing the quotes. Use "/<div class=\"?body\"?>(.*?)<\/div>/sui".
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