Python请求 - 打印整个http请求（原始）？ [英] Python requests - print entire http request (raw)?

问题描述

使用 requests 模块，有没有办法打印原始HTTP请求？

While using the requests module, is there any way to print the raw HTTP request?

我不想只是标题，我想要请求行，标题和内容打印输出。是否有可能看到最终由HTTP请求构造的内容？

I don't want just the headers, I want the request line, headers, and content printout. Is it possible to see what ultimately is constructed from HTTP request?

推荐答案

自v1.2.3起请求添加了PreparedRequest对象。根据文档它包含将发送到服务器的确切字节。

Since v1.2.3 Requests added the PreparedRequest object. As per the documentation "it contains the exact bytes that will be sent to the server".

可以使用它来打印请求，如下所示：

One can use this to pretty print a request, like so:

import requests

req = requests.Request('POST','http://stackoverflow.com',headers={'X-Custom':'Test'},data='a=1&b=2')
prepared = req.prepare()

def pretty_print_POST(req):
    """
    At this point it is completely built and ready
    to be fired; it is "prepared".

    However pay attention at the formatting used in 
    this function because it is programmed to be pretty 
    printed and may differ from the actual request.
    """
    print('{}\n{}\n{}\n\n{}'.format(
        '-----------START-----------',
        req.method + ' ' + req.url,
        '\n'.join('{}: {}'.format(k, v) for k, v in req.headers.items()),
        req.body,
    ))

pretty_print_POST(prepared)

产生：

-----------START-----------
POST http://stackoverflow.com/
Content-Length: 7
X-Custom: Test

a=1&b=2

然后你可以发送实际的请求：

Then you can send the actual request with this:

s = requests.Session()
s.send(prepared)

这些链接是最新的文档可用，因此它们可能会更改内容：
高级 - 准备好的请求和 API - 低级别课程

These links are to the latest documentation available, so they might change in content: Advanced - Prepared requests and API - Lower level classes

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