如何在Python 3中解析原始HTTP请求？ [英] How to parse raw HTTP request in Python 3?

问题描述

我正在寻找一种在Python 3中解析http请求的本地方法。

I am looking for a native way to parse an http request in Python 3.

这个问题显示了在Python 2中实现它的方法，但现在使用已弃用的模块（和Python 2），我正在寻找一种在Python 3中实现它的方法。

This question shows a way to do it in Python 2, but uses now deprecated modules, (and Python 2) and I am looking for a way to do it in Python 3.

我主要想知道请求什么资源并解析标头和简单的请求。 （即）：

I would mainly like to just figure out what resource is requested and parse the headers and from a simple request. (i.e):

GET /index.html HTTP/1.1
Host: localhost
Connection: keep-alive
Cache-Control: max-age=0
Upgrade-Insecure-Requests: 1
User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/52.0.2743.116 Safari/537.36
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8
Accept-Encoding: gzip, deflate, sdch
Accept-Language: en-US,en;q=0.8

有人能告诉我解析这个请求的基本方法吗？

Can someone show me a basic way to parse this request?

推荐答案

你可以使用 email.message.Message 电子邮件 课程标准库中的$ c> 模块。

You could use the email.message.Message class from the email module in the standard library.

通过修改您链接的问题的答案，是一个解析HTTP头的Python3示例。

By modifying the answer from the question you linked, below is a Python3 example of parsing HTTP headers.

假设您要创建一个包含所有标题字段的字典：

Suppose you wanted to create a dictionary containing all of your header fields:

import email
import pprint
from io import StringIO

request_string = 'GET / HTTP/1.1\r\nHost: localhost\r\nConnection: keep-alive\r\nCache-Control: max-age=0\r\nUpgrade-Insecure-Requests: 1\r\nUser-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/52.0.2743.116 Safari/537.36\r\nAccept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8\r\nAccept-Encoding: gzip, deflate, sdch\r\nAccept-Language: en-US,en;q=0.8'

# pop the first line so we only process headers
_, headers = request_string.split('\r\n', 1)

# construct a message from the request string
message = email.message_from_file(StringIO(headers))

# construct a dictionary containing the headers
headers = dict(message.items())

# pretty-print the dictionary of headers
pprint.pprint(headers, width=160)

如果你在python提示符下运行它，结果将如下所示：

if you ran this at a python prompt, the result would look like:

{'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8',
 'Accept-Encoding': 'gzip, deflate, sdch',
 'Accept-Language': 'en-US,en;q=0.8',
 'Cache-Control': 'max-age=0',
 'Connection': 'keep-alive',
 'Host': 'localhost',
 'Upgrade-Insecure-Requests': '1',
 'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/52.0.2743.116 Safari/537.36'}

这篇关于如何在Python 3中解析原始HTTP请求？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！