如何关闭从DOM插入MySQL的PHP循环 [英] How to close PHP loop that inserts from DOM into MySQL
问题描述
这个问题对于stackoverflow可能有点具体,但在这里。我有一个PHP文件,它采用HTML,将其写入一个新文件,将文件名插入数据库...一切正常。
This question may be a bit specific for stackoverflow, but here it is. I have a php file that is taking html, writing it to a new file, inserting the file name into a database...all that works fine.
现在我想要使用DOM提取html中的链接。我从这里获得了代码并获取以下内容错误:
Now I want to extract the links in the html, using DOM. I got code from here and get the following error:
解析错误:语法错误,第72行意外$ end ...
Parse error: syntax error, unexpected $end ... on line 72
看起来似乎我忘了关闭某些东西或者毫无疑问地关闭了某些东西。但是,唯一的新代码来自上面的链接,它似乎是有序的。但是我是DOM和PHP的新手,所以也许你可以提供帮助。任何指针都表示赞赏。以下是我添加的内容:
It would seem that I forgot to close something or closed something unsuspectingly. However the only new code is from the above link and it appears to be in order. However I am new to DOM and PHP, so perhaps you can help. Any pointers are appreciated. Here is what I have added:
$dom = new DOMDocument();
@$dom->loadHTML($curl_scraped_page);
$xpath = new DOMXPath($dom);
$hrefs = $xpath->evaluate("/html/body//a");
//the above works fine, but when I add the loop bellow it fails
for ($i = 0; $i < $hrefs->length; $i++) {
$href = $hrefs->item($i);
$url = $href->getAttribute('href');
storeLink($url,$target_url);
function storeLink($url) {
$query = "INSERT INTO happyturtle (ad2, ad3) VALUES ('$url', '$gathered_from')";
mysql_query($query) or die('Error, insert query failed');
if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
echo "1 record added";
}
为了完整起见,这里是包含新位的整个代码:
For the sake of completeness, here is the whole code with the new bits included:
<html>
<body>
<?
$urls=explode("\n", $_POST['url']);
$proxies=explode("\n", $_POST['proxy']);
for ( $counter = 0; $counter <= 6; $counter++) {
for ( $count = 0; $count <= 6; $count++) {
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,$urls[$counter]);
curl_setopt($ch, CURLOPT_HTTPPROXYTUNNEL, 0);
curl_setopt($ch, CURLOPT_PROXY,$proxies[$count]);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST,'GET');
curl_setopt ($ch, CURLOPT_HEADER, 1);
curl_exec ($ch);
$curl_scraped_page = curl_exec($ch);
$FileName = rand(0,100000000000);
$FileHandle = fopen($FileName, 'w') or die("can't open file");
fwrite($FileHandle, $curl_scraped_page);
$dom = new DOMDocument();
@$dom->loadHTML($curl_scraped_page);
$xpath = new DOMXPath($dom);
$hrefs = $xpath->evaluate("/html/body//a");
$hostname="****";
$username="****";
$password="****";
$dbname="****";
$usertable="****";
$con=mysql_connect($hostname,$username, $password) or die ("<html><script language='JavaScript'>alert('Unable to connect to database! Please try again later.'),history.go(-1)</script></html>");
mysql_select_db($dbname ,$con);
for ($i = 0; $i < $hrefs->length; $i++) {
$href = $hrefs->item($i);
$url = $href->getAttribute('href');
storeLink($url,$target_url);
function storeLink($url) {
$query = "INSERT INTO happyturtle (ad2, ad3) VALUES ('$url', '$gathered_from')";
mysql_query($query) or die('Error, insert query failed');
$sql="INSERT INTO happyturtle (time, ad1)
VALUES
('$FileName','$domains')";
}
mysql_close($con);
fclose($FileHandle);
curl_close($ch);
echo $FileName;
echo "<br/>";
}
}
?>
</body>
</html>
推荐答案
尝试正确缩进代码。
然后你会看到以下 for
循环:
You'll then see that the following for
loop :
for ( $counter = 0; $counter <= 6; $counter++) {
未关闭:没有结尾}
对应于其开头 {
is not closed : there is no ending }
that correspond to its opening {
(实际上,消息表明某处缺少}
,这在缩进代码时会显示 - 可能是这个for-loop没有关闭,或者是你的其他 {
;由你决定应该关闭什么,取决于你的代码的逻辑)
(Well, actually, the message indicates there is a missing }
somewhere, and this is shown when indenting the code -- it might be this for-loop that's not closed, or one of your other {
; up to you to find out what should be closed, depending on your code's logic)
或许问题是你有两个用于
循环看起来有点相同:
Or maybe the problem is that you have two for
loops that looks kind of the same :
for ( $counter = 0; $counter <= 6; $counter++) {
for ( $count = 0; $count <= 6; $count++) {
// Some code
} // closing of the inner for-loop
// Here, the first for-loop is not closed
所以,要么:
- 关闭外部
- 或删除它,如果它没用。
- close the outer
for
-loop, - or remove it, if it's not useful.
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