条件的长度> 1,仅使用第一个元素 [英] The condition has length > 1 and only the first element will be used

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问题描述

我有一个数据框,旅行:

I have a dataframe, trip:

> head(trip.mutations)
  Ref.y Variant.y
1 T     C 
2 G     C 
3 A     C  
4 T     C 
5 C     A 
6 G     A 

我想添加第三列mutType,遵循以下规则:

I want to add a third column, mutType, that follows these rules:

for (i in 1:nrow(trip)) {
   if(trip$Ref.y=='G' & trip$Variant.y=='T'|trip$Ref.y=='C' & trip$Variant.y=='A') {
      trip[i, 'mutType'] <- "G:C to T:A"
   }
   else if(trip$Ref.y=='G' & trip$Variant.y=='C'|trip$Ref.y=='C' & trip$Variant.y=='G') {
      trip[i, 'mutType'] <- "G:C to C:G"
   }
   else if(trip$Ref.y=='G' & trip$Variant.y=='A'|trip$Ref.y=='C' & trip$Variant.y=='T') {
      trip[i, 'mutType'] <- "G:C to A:T"
   }
   else if(trip$Ref.y=='A' & trip$Variant.y=='T'|trip$Ref.y=='T' & trip$Variant.y=='A') {
      trip[i, 'mutType'] <- "A:T to T:A"
   }
   else if(trip$Ref.y=='A' & trip$Variant.y=='G'|trip$Ref.y=='T' & trip$Variant.y=='C') {
      trip[i, 'mutType'] <- "A:T to G:C"
   }
   else if(trip$Ref.y=='A' & trip$Variant.y=='C'|trip$Ref.y=='T' & trip$Variant.y=='G') {
      trip[i, 'mutType'] <- "A:T to C:G"
   }
}

但我收到错误:

Warning messages:
1: In if (trip$Ref.y == "G" & trip$Variant.y == "T" | trip$Ref.y ==  ... :
  the condition has length > 1 and only the first element will be used

我不认为我的逻辑陈述应该是生成向量,但也许我是错误的东西.travel $ mutType 应该最终看起来像这样:

I don't think my logical statements should be producing vectors, but maybe I'm missing something. trip$mutType should end up looking like this:

mutType
A:T to G:C
G:C to C:G
A:T to C:G
A:T to G:C
G:C to T:A
G:C to A:T

有人能发现这里有什么问题吗?我需要吗? ||而不是|也许?

Can anyone spot what's wrong here? Do I need || instead of | perhaps?

推荐答案

您收到错误,因为如果只能评估长度为1的逻辑向量。

You get the error because if can only evaluate a logical vector of length 1.

也许你错过了& 之间的区别( | )和&& || )。较短的版本在元素方面有效,较长的版本仅使用每个向量的第一个元素,例如:

Maybe you miss the difference between & (|) and && (||). The shorter version works element-wise and the longer version uses only the first element of each vector, e.g.:

c(TRUE, TRUE) & c(TRUE, FALSE)
# [1] TRUE FALSE

# c(TRUE, TRUE) && c(TRUE, FALSE)
[1] TRUE

你不需要 if 声明:

mut1 <- trip$Ref.y=='G' & trip$Variant.y=='T'|trip$Ref.y=='C' & trip$Variant.y=='A'
trip[mut1, "mutType"] <- "G:C to T:A"

这篇关于条件的长度> 1,仅使用第一个元素的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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