PHP底片不断添加 [英] PHP negatives keep adding

问题描述

我这里有这个代码......

I have this code here...

$remaining = 0;
foreach($clientArrayInvoice as $key=>$row){
            $remaining = $remaining + $row['total'];   
}

它做什么，需要总值并将它们加起来.. 。但是当我有值为负数的时候，当我有 -51.75 和 -17.85 我得到 -69.60 它应该是 -33.90 我该如何解决这个问题？

What it does, it takes the values of total and adds them up...but when I have values that are negatives, it adds them up as well for an example when I have -51.75 and -17.85 I get -69.60 which it should be -33.90 how do I fix this?

`-33.901是我期待的值，因为当我想减去它的两个底片时，不要添加

`-33.901 is the value I am expecting because when its two negatives I would like to subtract, not add

谢谢，
J

Thanks, J

推荐答案

这可能有所帮助：

(-51.75) + (-17.85) = -69.60
(-51.75) - (-17.85) = -33.90

假设您总是需要添加第二个数字而不管它的符号，您需要使用 PHP abs 功能，带 $ row ['total'] ：

Assuming you always need to add the second number regardless of it's sign, you need to take the absolute value by using the PHP abs function with $row['total']:

$remaining = 0;
foreach($clientArrayInvoice as $key=>$row){
    $remaining = $remaining + abs($row['total']);   
}

---

回应你的意思在您的问题中更新：

---

In response to what you updated in your question:

-33.90是我期待的值，因为当它的两个底片我想减去，而不是添加

-33.90 is the value I am expecting because when its two negatives I would like to subtract, not add

这几乎是使用 abs 函数的功能。我可以将上面的代码片段重写为：

This is pretty much what using the abs function does. I could rewrite the above code snippet as:

$remaining = 0;
foreach($clientArrayInvoice as $key=>$row) {
    if ($remaining >= 0) {
        $remaining = $remaining + abs($row['total']);   
    }
    else {
        $remaining = $remaining - abs($row['total']);   
    }
}

然而，这与使用简单完全相同PHP abs 函数，因为你总是将 $ row ['total'] 的大小添加到 $剩余。

However, this does the exact same thing as simply using the PHP abs function, since you are always adding the magnitude of $row['total'] to $remaining.

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