仅着色特定像素 [英] Coloring only specific pixels

问题描述

我有一个表示大脑图像的矩阵，每个（i，j）位置的值介于0和1之间。我正在应用颜色贴图，因此值为1的像素为红色，0为黄色，在中间获取中间价值。现在，我想要的是那些值大于0.8的像素根据色彩图获得颜色，其余变得透明（即它们没有得到任何颜色），这样我就可以用另一个大脑图像覆盖这个图像并识别高活动区域。我怎么做？

I have a matrix representing an image of brain with each (i,j) position having a value between 0 and 1. I am applying a color map, so that those pixels with value 1 are red and 0 are yellow, those in between get intermediary values. Now, what i want is that those pixels having values above 0.8 get color according to colormap and rest become trasparent(that is they dont get any color), so that i can overlay this image with the another image of brain and identify high activity region. How do i do this ?

我有这样的图像

i have images like this

我只想要亮黄色的部分，这样我就可以将它与其他图像叠加在一起并得到类似的东西。

I want only the bright yellow part, so that i can overlay it with other image and get something like this.

编辑：

我按照Jigg建议的方法，但最近观察到最终图像被旋转和反转，任何想法为什么？

I followed the method suggested by Jigg, but recently observed that the final image was rotated and inverted , any idea why ?

推荐答案

这是另一种选择，创建一个复制灰度脑图像的3层阵列（ imagesc 将按比例缩放每一层，得到相等的r，g和b值 - >灰度级。）

Here is another option, create a 3-layers array replicating your grayscale brain image (imagesc will scale each layer similarly resulting in equal r, g, and b values -> levels of gray).

GrayBckgnd = repmat(brain, [1, 1, 3]);
data = …

然后用活动数据覆盖它：

Then overlay it with the activity data:

imagesc(GrayBcknd);
hold on;
DataImg = imagesc(data);
set(DataImg, 'AlphaData', im2double(data>0.8));
colormap jet; % or any other colormap.

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