全景图像摄影测量：如何计算范围？ [英] Panoramic Image Photogrametry: How to calculate range?

问题描述

假设我拍摄了两幅垂直偏移为H的全景图像，每张图像都以尺寸为Xm和Ym的equirectangular投影呈现。为此，我将全景相机放在A位置并拍摄图像，然后移动相机H米并拍摄另一张图像。

Assume that I took two panoramic image with vertical offset of H and each image is presented in equirectangular projection with size Xm and Ym. To do this, I place my panoramic camera at position say A and took an image, then move camera H meter up and took another image.

我知道坐标为X1，Y1的图像1中的点是图像2上坐标为X2和Y2的相同点（假设X1 = X2，因为我们有只有垂直偏移）。

I know that a point in image 1 with coordinate of X1,Y1 is the same point on image 2 with coordinate X2 and Y2(assuming that X1=X2 as we have only vertical offset).

我的问题是如何计算所选点的范围（知道其X1和Y1在图像1上的点及其位置图像2是来自A点的X2和Y2（相机在拍摄图像时为1）。

My question is that How I can calculate the range of selected of point (the point that know its X1and Y1 is on image 1 and its position on image 2 is X2 and Y2 from the Point A (where camera was when image no 1 was taken.).

推荐答案

是的，你可以做到 - 坚持!!!

Yes, you can do it - hold on!!!

关键的事情 y =镜头的焦距 - 现在我可以做到!!!

Key thing y = focal length of your lens - now I can do it!!!

所以，我认为你的问题可以更简单地说，如果你移动你的相机（在图中的右侧）上涨 H 米，一个点向下移动 p 从新位置拍摄的图像中的像素。

So, I think your question can be re-stated more simply by saying that if you move your camera (on the right in the diagram) up H metres, a point moves down p pixels in the image taken from the new location.

如果您想象从侧面看，在拍摄照片时，就像这样。

Like this if you imagine looking from the side, across you taking the picture.

如果您知道相机CCD的微米间距与其规格有关，则可以转换 p 从像素到米来匹配 H 的单位。

If you know the micron spacing of the camera's CCD from its specification, you can convert p from pixels to metres to match the units of H.

从相机到场景平面的范围由 x + y 给出（两者都是红色的底部），和

Your range from the camera to the plane of the scene is given by x + y (both in red at the bottom), and

x=H/tan(alpha)

y=p/tan(alpha)

所以你的范围是

R = x + y = H/tan(alpha) + p/tan(alpha)

和

alpha = tan inverse(p/y)

其中y是镜头的焦距。因为 y 可能是50毫米，它可以忽略不计，所以，到一个非常合理的近似值，你的范围是

where y is the focal length of your lens. As y is likely to be something like 50mm, it is negligible, so, to a pretty reasonable approximation, your range is

H/tan(alpha)

和

alpha = tan inverse(p in metres/focal length)

或者，通过相似的三角形

Or, by similar triangles

Range =     H x focal length of lens
        --------------------------------
         (Y2-Y1) x CCD photosite spacing

非常小心地把所有东西都放在米里。

being very careful to put everything in metres.

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