将Matlab pdollar工具箱代码转换为Octave后读取框架 [英] Reading frame after converting Matlab pdollar toolbox code to Octave

问题描述

我想使用pdollar工具箱阅读视频。我有几个视频文件，我试图应用acfDetect分类器。但是，我没有得到正确的输出。在检查时，我发现对于Matlab和Octave，帧（矩阵）的数据不匹配。随附的照片将清楚这个问题。我试图打印框架的值，这就是我得到的：

I want to read a video using pdollar toolbox. I have few video files upon whom I am trying to apply the acfDetect classier. However, I don't get the correct output. On checking, I found that the data of the frame (the matrix) do not match, for Matlab and Octave. The question will be clear with the attached pics. I tried to print the value of the frame and this is what I get:

Matlab输出：

< a href =https://i.stack.imgur.com/K7FQb.png =nofollow noreferrer>

八度输出：

作为一个试验，我看到将Octave值乘以255（RGB max）给出了一个近似于Matlab的值。但是当我这样做时，我收到以下错误：

As a hit an trial, I saw that multiplying Octave values by 255 (RGB max) gives me an approx to the Matlab values. But when I do so, I get the following error:

> >> runonVideos
处理11-50-48--11-50-58_resized.mp4 ...
错误：rgbConvertMex：对于浮点数，I中的所有值必须小于1.
错误：调用来自
rgbConvert第80行第2列
chnsPyramid第133行第2列
acfDetect_modified> acfDetectImg第74行第2列
acfDetect_modified第41行第19行
行人在线检测33列11
runonVideos第8行第5列

基本上，Matlab得到相同的值（0-255）但不是'为这里所述的函数给出任何这样的错误：rgbConvertMex。我无法理解问题究竟在哪里。

Essentially, Matlab gets the same value (0-255) but doesn't give any such error for the function stated here: rgbConvertMex.I am unable to understand where exactly is the problem.

如果我能得到与Matlab，我的问题将在很大程度上得到解决。

If I am able to get the same value as in Matlab, my problem will be solved to a large extent.

Octave代码在这里：

The Octave code is here:

> % Output text file
    outFile = fopen(['C:\devwork\matlab\boosted\detection\',videoFname(1:end-4),'_detections.txt'],'w+');
    % videoPlayer = vision.VideoPlayer;
    vObj = VideoReader('C:\devwork\matlab\boosted\resizedVideos\11-50-48--11-50-58_resized.mp4');
    %fprintf vObj;
    % videoFwriter = vision.VideoFileWriter('result3_newAnnLdcf+.mp4','FileFormat','MPEG4','FrameRate',vObj.FrameRate);
    tic
    while hasFrame(vObj)

        frame = readFrame(vObj);
        %fprintf(frame);
        % frame = imresize(frame,0.5);
        bbs = acfDetect_modified(frame,detector);
        % displayFrame = frame;
        bbs = bbs(:,1:4);
        bbs = round(bbs);
%         if ((bbs(1,:) >= 1152) || (bbs(2,:) >= 648))
%             disp('BB exceeds bounds')
%             disp(bbs)
%         end
        % displayFrame = insertShape(displayFrame,'Rectangle',bbs,'LineWidth',2,'Color','red'); 
        fprintf(outFile,'%d ',reshape(bbs,numel(bbs),1));
        fprintf(outFile,'\n');
        % videoPlayer.step(displayFrame);
        % step(videoFwriter,displayFrame);
    end
    toc
    fclose(outFile);
    fprintf('done \n');
    % release(videoPlayer);
    % release(videoFwriter);
end

编辑1：在Matlab中，我尝试将v = v * 255更改为v = uint8（v）
但现在我将所有值都设为0或1.

Edit 1: In Matlab, I tried changing v=v*255 to v=uint8(v) But now I get all values as either 0 or 1.

编辑2：

代码截图：

Screenshot of the code:

输出屏幕截图：

编辑3：根据建议，Octace中的代码行31更改为： v = uint8（v * 255 ）;
这确实给出了整数的结果，但它们仍然与Matlab的结果不同。我猜它一定是我的乘法因子为255的问题。但是这仍然没有解决。

Edit 3: As suggested, code line 31 in Octace was changed to:v=uint8(v*255); This does give result in integers but they are still not same as that of Matlab. I am guessing it must be some issue with my multiplication factor of 255. But this is still not resolved.

新输出的屏幕截图：

推荐答案

您正在寻找的功能是 im2uint8 ，由图像包提供。

The function you're looking for is im2uint8, which is provided by the image package.

这可以输入类在[0,1]范围内加倍并将其转换为uint8图像，相应的值在[0,255]范围内。

This can take an input of class double in the range [0,1] and convert it to a uint8 image, with corresponding values in the range [0,255] accordingly.

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