PHP是否包含相对于文件或调用代码的路径？ [英] Are PHP include paths relative to the file or the calling code?

问题描述

我无法理解有关PHP相对包含路径的规则集。如果我运行文件A.PHP-并且文件A.PHP包括包含文件C.PHP的文件B.PHP，那么C.PHP的相对路径是否与B.PHP的位置或A的位置有关.PHP？也就是说，从哪个文件调用include，或者只调用当前工作目录是什么以及什么决定当前工作目录是否重要？

I'm having trouble understanding the ruleset regarding PHP relative include paths. If I run file A.PHP- and file A.PHP includes file B.PHP which includes file C.PHP, should the relative path to C.PHP be in relation to the location of B.PHP, or to the location of A.PHP? That is, does it matter which file the include is called from, or only what the current working directory is- and what determines the current working directory?

推荐答案

它与主脚本有关，在本例中为A.php。请记住 include（）只需将代码插入当前运行的脚本中。

It's relative to the main script, in this case A.php. Remember that include() just inserts code into the currently running script.

是的，包含从哪个文件调用是否重要

That is, does it matter which file the include is called from

否。

如果你想 make 那么重要，并做一个相对于B.php的包含，请使用 __ FILE __ 常量（或 __ DIR __ 自PHP 5.2 IIRC），它总是指向代码行所在的文字当前文件。

If you want to make it matter, and do an include relative to B.php, use the __FILE__ constant (or __DIR__ since PHP 5.2 IIRC) which will always point to the literal current file that the line of code is located in.

include(dirname(__FILE__)."/C.PHP");

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