AppleScript 相对于脚本位置的路径 [英] AppleScript path relative to script location

问题描述

我正在尝试启动与我的脚本位于同一目录中的文件夹的 Finder 窗口.当我运行下面的代码时，它会启动一个空白的 Finder 窗口，该窗口设置为脚本路径而不是文件夹.

I'm trying to launch a Finder window of a folder that's in the same directory as my script. When I run the code below, it launches a blank Finder window set to the path of the script not to the folder.

tell application "Finder"
    tell application "Finder" to make new Finder window
    set file_path to (path to me) as text
    set target of Finder window 1 to file_path
end tell

如何获取脚本文件夹的路径，而不是脚本?

How can I get the path to the folder of the script, not the script?

推荐答案

你已经接近了.您不需要文件的文本版本，您只需要文件本身，然后您可以向 Finder 询问该文件的容器:

You were close. You do not need the text version of the file, you only need the file itself, then you can ask Finder for that file's container:

tell application "Finder"
    tell application "Finder" to make new Finder window
    set file_path to (path to me)
    set target of Finder window 1 to file_path's container
end tell

这篇关于AppleScript 相对于脚本位置的路径的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！