我可以扩展#include文件内联而不扩展指令吗？ [英] Can I expand #include files inline and not expand directives?

问题描述

我正在尝试简化应用程序的部署。为了在最终用户的机器上构建最终应用程序，需要编译几个 C 文件。这意味着需要随应用程序一起提供数十个头文件。我希望能够预先包含包含文件的内容，但我还需要能够控制指令（ #if 等，包括内衬后。我找不到一个cpp选项，它允许我只包含标题，而不进行其余的预处理。我有什么选择？

I'm trying to simplify the deployment of an application. In order to build the final application on an end-user's machine, a couple of C files need to be compiled. This means that dozens of header files need to be shipped along with the application. I'd like to be able to pre-include the contents of the include files, but I also need to be able to control the directives (#if, etc.) after the includes are in-lined. I can't find a cpp option that lets me just include headers, without doing the rest of the preprocessing. What are my options?

示例：

File1.h

void dummy_func()
{return;}

File2.h

#if INCLUDE_FILE1
    #include "file1.h"
#endif

最后，我想要一个文件说：

In the end, I want a file that says:

#if INCLUDE_FILE1
void dummy_func()
{return;}
#endif

推荐答案

由于双重包含警卫，内联#includes的工具可能会导致一个巨大的文件，其中很多标题完全在#ifndefs内部，不匹配。在极端情况下，它甚至可能导致无限大小的输出文件，如果包含是递归的（由于双重包含保护通常不是问题）。

Due to double-include guards, a tool that inlines #includes may cause a giant file, where a lot of the headers are entirely inside #ifndefs that don't match. In extreme cases, it may even cause an infinite-size output file, if includes are recursive (which normally isn't a problem because of the double-include guards).

我刚刚确认此代码编译成功：

I just confirmed that this code compiles successfully:

main.cpp：

#include "a.h"
int main() { return 0; }

啊：

#ifndef A_H_INCLUDED
#define A_H_INCLUDED

#include "b.h"

#endif

bh：

#ifndef B_H_INCLUDED
#define B_H_INCLUDED

#include "a.h"

#endif

由于你想保持ifdefs不变和未解析，一个内联 #includes 的工具会导致无限输出。

Since you want to keep ifdefs untouched and unparsed, a tool that inlines #includes would cause infinite output.

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