用R中的另一个值替换多列数据帧中的数字的出现次数 [英] Replacing occurrences of a number in multiple columns of data frame with another value in R
问题描述
ETA：顺便说一下，下面的内容是不必迭代我的整个列向量集，以防万一这是一个提议的解决方案（只是做了已知的事情）一次只能工作一次。）
ETA: the point of the below, by the way, is to not have to iterate through my entire set of column vectors, just in case that was a proposed solution (just do what is known to work once at a time).
有很多替换单个 R中的数据框的向量与其他值。
There's plenty of examples of replacing values in a single vector of a data frame in R with some other value.
- Replace a value in a data frame based on a conditional (
if) statement in R - replace numbers in data frame column in r [duplicate]
以及如何用其他东西替换 NA 的所有值：
And also how to replace all values of NA with something else:
- How to replace all values in a data.frame with another ( not 0) value
我正在寻找的是类似于上一个问题，但基本上是试图用另一个值替换一个值。对于多列符合条件的情况，或者只是尝试从多个列的前两个问题执行操作，我无法生成映射到我的实际数据帧的逻辑值数据帧。
What I'm looking for is analogous to the last question, but basically trying to replace one value with another. I'm having trouble generating a data frame of logical values mapped to my actual data frame for cases where multiple columns meet a criteria, or simply trying to do the actions from the first two questions on more than one column.
一个例子：
data <- data.frame(name = rep(letters[1:3], each = 3), var1 = rep(1:9), var2 = rep(3:5, each = 3))
data
name var1 var2
1 a 1 3
2 a 2 3
3 a 3 3
4 b 4 4
5 b 5 4
6 b 6 4
7 c 7 5
8 c 8 5
9 c 9 5
并且我想在 var1 和 var2 4 的所有值$ c>要 10 。
我确信这是基本的，我只是没想过它恰当。我一直在尝试这样的事情：
I'm sure this is elementary and I'm just not thinking through it properly. I have been trying things like:
data[data[, 2:3] == 4, ]
这不起作用，但如果我对数据[，2] 而不是数据[，2：3] ，一切正常。似乎逻辑测试（如 is.na（））可以处理多行/列，但数字比较效果不佳？
That doesn't work, but if I do the same with data[, 2] instead of data[, 2:3], things work fine. It seems that logical test (like is.na()) work on multiple rows/columns, but that numerical comparisons aren't playing as nicely?
感谢您的任何建议！
推荐答案
您想在整个数据框中搜索任何内容与您尝试替换的值匹配的值。与运行逻辑测试的方式相同，例如将所有缺失值替换为10 ..
you want to search through the whole data frame for any value that matches the value you're trying to replace. the same way you can run a logical test like replacing all missing values with 10..
data[ is.na( data ) ] <- 10
你也可以用10s替换所有4s。
you can also replace all 4s with 10s.
data[ data == 4 ] <- 10
至少我认为这就是你所追求的？
at least i think that's what you're after?
让我们说你想忽略第一行（因为它是所有字母）
and let's say you wanted to ignore the first row (since it's all letters)
# identify which columns contain the values you might want to replace
data[ , 2:3 ]
# subset it with extended bracketing..
data[ , 2:3 ][ data[ , 2:3 ] == 4 ]
# ..those were the values you're going to replace
# now overwrite 'em with tens
data[ , 2:3 ][ data[ , 2:3 ] == 4 ] <- 10
# look at the final data
data
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