模板继承的问题 [英] problem with template inheritance
问题描述
我试图理解我在这段代码上遇到错误:
(错误在g ++ unix编译器下.VS编译正常)
I'm trying to understand whay i get an error on this code: (the error is under g++ unix compiler. VS is compiling OK)
template<class T> class A {
public:
T t;
public:
A(const T& t1) : t(t1) {}
virtual void Print() const { cout<<*this<<endl;}
friend ostream& operator<<(ostream& out, const A<T>& a) {
out<<"I'm "<<typeid(a).name()<<endl;
out<<"I hold "<<typeid(a.t).name()<<endl;
out<<"The inner value is: "<<a.t<<endl;
return out;
}
};
template<class T> class B : public A<T> {
public:
B(const T& t1) : A<T>(t1) {}
const T& get() const { return t; }
};
int main() {
A<int> a(9);
a.Print();
B<A<int> > b(a);
b.Print();
(b.get()).Print();
return 0;
}
此代码出现以下错误:
main.cpp:在成员函数'const T& B :: get()const':
main.cpp:23:错误:'t'未在此范围内声明
main.cpp: In member function 'const T& B::get() const':
main.cpp:23: error: 't' was not declared in this scope
它确实当我将B的代码改为此时编译:
It did compiled when i changed the code of B to this:
template<class T> class B : public A<T> {
public:
B(const T& t1) : A<T>(t1) {}
const T& get() const { return A<T>::t; }
};
我只是无法理解第一个代码有什么问题......
每次我真的需要写A ::是没有意义的......
I just cant understand what is the problem with the first code...
It doesn't make sense that i really need to write "A::" every time...
推荐答案
你可以也可以使用 this-> t
来访问基类模板成员。
You can also use this->t
to access the base class template member.
在中B :: get()
,名称 t
不依赖于模板参数 T
,所以它不是一个从属名称。基类 A< T>
显然取决于模板参数 T
,因此是依赖基类。在从属基类中不查找非依赖名称。 有关原因的详细说明,请参阅C ++ FAQ Lite 。
In B::get()
, the name t
is not dependent on the template parameter T
, so it is not a dependent name. Base class A<T>
is obviously dependent on the template parameter T
and is thus a dependent base class. Nondependent names are not looked up in dependent base classes. A detailed description of why this is the case can be found in the C++ FAQ Lite.
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