为什么首选非虚拟接口? [英] Why is it preferred to have non-virtual interfaces?
问题描述
我正在浏览 http://www.gotw.ca/publications/mill18。 hbm 由Herb Sutter撰写。作者提到,编写非虚拟接口会将接口规范与实现细节(即内部可自定义行为)分开。
I am going through this article http://www.gotw.ca/publications/mill18.htm by Herb Sutter. The author mentions that writing non-virtual interfaces separates the interface specification from the "implementation details (namely the internally customizable behavior)"
// Example 1: A traditional base class.
//
class Widget
{
public:
// Each of these functions might optionally be
// pure virtual, and if so might or might not have
// an implementation in Widget; see Item 27 in [1].
//
virtual int Process( Gadget& );
virtual bool IsDone();
// ...
};
上面的例子指定了哪种实现细节(或可自定义的行为)?我对上面的代码有什么问题感到有些困惑,这需要我们有非虚拟接口
What kind of implementation detail (or customizable behavior) does the above example specify? I am slightly confused about what is wrong with the above code, which requires us to have non-virtual interfaces
推荐答案
按可自定义的行为
它表示由不同的派生类
提供的实现,即将从派生的类接口
。
By customizable behavior
it means the implementation provided by different Derived Classes
, i.e the classes which will derive from your Interface
.
考虑一下:
class IMachine
{
public:
int ProcessJob()
{
cout << "Processing Job in By-Default way" << endl;
}
virtual int ProcessOrder()
{
cout << "Processing Order in By-Default way" << endl;
}
};
class CMachine_A : public IMachine
{
public:
int ProcessJob()
{
cout << "Processing Job in Machine A's way" << endl;
}
int ProcessOrder()
{
cout << "Processing Order in Machine A's way" << endl;
}
};
class CMachine_B : public IMachine
{
public:
int ProcessJob()
{
cout << "Processing Job in Machine B's way" << endl;
}
int ProcessOrder()
{
cout << "Processing Order in Machine B's way" << endl;
}
};
IMachine *pMachine;
CMachine_A oMachineA;
CMachine_B oMachineB;
pMachine = &oMachineA;
pMachine->ProcessJob();
pMachine = &oMachineB;
pMachine->ProcessJob();
Output:
Processing Job in By-Default way
Processing Job in By-Default way
因此,在上面的示例中,即使 pMachine
指向不同的具体实现(读取:派生类),输出也是相同的,无论是选择的实现/派生类。也就是说,机器A和机器B的可自定义行为
未生效或未兑现。因此,通过非虚拟 IMachine :: ProcessJob()
,接口 IMachine
具有分离/忽略/禁止处理作业的方式,无论机器的类型如何( CMachine_A
或 CMachine_B
使用。
So, in above example even though pMachine
points to different concrete implementations (read: derived classes), the output is same irrespective of chosen implementation/derived class. That is, the customizable behavior
of Machine A and Machine B is not coming in-effect or not honored. So, by having non virtual IMachine::ProcessJob()
, the interface IMachine
has separated/ignored/suppressed the way in which the Job will get processed irrespective of the type of Machine (CMachine_A
or CMachine_B
) which is used.
现在考虑一下:
IMachine *pMachine;
CMachine_A oMachineA;
CMachine_B oMachineB;
pMachine = &oMachineA;
pMachine->ProcessOrder();
pMachine = &oMachineB;
pMachine->ProcessOrder();
Output:
Processing Order in Machine A's way
Processing Order in Machine B's way
这里,当 pMachine
指向不同的具体实现(读取:派生类)时,输出是根据所选的实现/派生类。也就是说,机器A和机器B的可自定义行为
即将生效或兑现。因此,通过虚拟 IMachine :: ProcessOrder()
,接口 IMachine
保留根据机器类型( CMachine_A
或 CMachine_B
)处理订单将被处理的选项/方式使用。
Here, when pMachine
points to different concrete implementations (read: derived classes), the output is according to the chosen implementation/derived class. That is, the customizable behavior
of Machine A and Machine B is coming in-effect or honored. So, by having virtual IMachine::ProcessOrder()
, the interface IMachine
has kept the option/way open in which the Order will get processed depending upon the type of Machine (CMachine_A
or CMachine_B
) which is used.
简而言之,因为接口 IMachine
保留了 ProcessOrder
as virtual
因此,不同的实现/派生类可以为函数<$ c $提供可自定义行为
c> ProcessOrder 。
In short, since the interface IMachine
has kept the ProcessOrder
as virtual
therefore different implementation/derived class can provide customizable behavior
for the function ProcessOrder
.
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