一次抽奖中有多个skshapenode？ [英] Multiple skshapenode in one draw?

问题描述

您好我已经绘制了skshapenodes连接我的图形中的节点以用于我的视觉*表示。

Hi I have drawn skshapenodes connecting the nodes in my graph for my visual a* representation.

for(int x=0; x<64; x++)
        {
            for(int y=0; y<48; y++)
            {
                PathFindingNode *node = [[gridToDraw objectAtIndex:x] objectAtIndex:y];
                for(int i=0; i< node.connections.count; i++)
                {
                    PathFindingNode *neighbor = [node.connections objectAtIndex:i];

                    SKShapeNode *line = [SKShapeNode node];
                    CGMutablePathRef pathToDraw = CGPathCreateMutable();
                    CGPathMoveToPoint(pathToDraw, NULL, node.position.x, node.position.y);
                    CGPathAddLineToPoint(pathToDraw, NULL, neighbor.position.x, neighbor.position.y);
                    line.path = pathToDraw;
                    line.lineWidth = 0.1f;
                    [line setStrokeColor:[UIColor blueColor]];
                    line.alpha = 0.1f;
                    [self addChild:line];
                }
            }
        }

有很多节点我的图表和这绘制了近22,000个形状。有没有办法可以在一次绘制调用中绘制这些形状，因为它们都是相同的，唯一的区别是它们的起点和终点位置。

There are lots of nodes in my graph and this draws almost 22,000 shapes. Is there a way I can draw these shapes in one draw call, as they are all the same, the only difference is the start and end location of them.

如果我使用了一个纹理，它将被加载一次，如何更改它的旋转以加入我的所有节点，如上所述。

If I used a texture instead, which would be loaded in once, how could I change the rotation of it to join all of my nodes up like above.

问候，

更新：

SKShapeNode *line = [SKShapeNode node];
        CGMutablePathRef pathToDraw = CGPathCreateMutable();

        for(int x=0; x<64; x++)
        {
            for(int y=0; y<48; y++)
            {
                PathFindingNode *node = [[gridToDraw objectAtIndex:x] objectAtIndex:y];
                for(int i=0; i< node.connections.count; i++)
                {
                    PathFindingNode *neighbor = [node.connections objectAtIndex:i];
                    CGPathMoveToPoint(pathToDraw, NULL, node.position.x, node.position.y);
                    CGPathAddLineToPoint(pathToDraw, NULL, neighbor.position.x, neighbor.position.y);
                }
            }
        }

        line.path = pathToDraw;
        line.lineWidth = 0.1f;
        [line setStrokeColor:[UIColor blueColor]];
        line.alpha = 0.1f;
        [self addChild:line];

我更新了我的代码，如上所示，这绘制了一个sknode，但它绘制了185次，为什么会这样？

I have updated my code to look like the above, this draws one sknode, but it draws 185 times, why is this?

推荐答案

我昨天将在类似的问题上回答这个问题，但它已经消失了。

I was going to answer this yesterday on a similar question but it disappeared.

您可以使用 CGPathAddPath 创建一个路径并将所有内容绘制为一个 SKShapeNode 合并路径。

You can create one path and draw everything as one SKShapeNode using CGPathAddPath to merge the paths as you go.

以下是一个例子：

SKEffectNode *effectNode = [[SKEffectNode alloc]init];
SKShapeNode  *shape = [[SKShapeNode alloc] init];
CGMutablePathRef myPath = CGPathCreateMutable();
CGPathAddArc(myPath, NULL, 0,0, 15, 0, M_PI*2, YES);

CGMutablePathRef pathTwo = CGPathCreateMutable();
CGPathAddArc(pathTwo, NULL, 50,0, 15, 0, M_PI*2, YES);     
CGPathAddPath(myPath, NULL, pathTwo);

CGMutablePathRef pathThree = CGPathCreateMutable();
CGPathAddArc(pathThree, NULL, 100,0, 15, 0, M_PI*2, YES);
CGPathAddPath(myPath, NULL, pathThree);

shape.path = myPath;

[effectNode addChild:shape];
[self addChild:effectNode];

effectNode.shouldRasterize = YES;  // if you don't rasterize it's horrifically slow.

这只是如何合并不同路径以创建一个的示例SKShapeNode 包含您正在寻找的所有视觉元素。您需要将此概念应用于您的代码。

This was just an example of how to merge the different paths to create one SKShapeNode that has all visual elements you are seeking. You'll need to apply this concept to your code.

我将结果 SKShapeNode 添加到 SKEffectNode 这样我就可以利用 shouldRasterize 属性来缓存形状，否则你的帧率会很糟糕。

I added the resulting SKShapeNode to an SKEffectNode so that I could utilize the shouldRasterize property to cache the shape, otherwise your framerate will be horrible.

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