联系存在于接触 [英] contact exists in contacts

问题描述

我的电话号码。有没有什么办法来检查是否存在于联系人数据库中的设备的电话号码或不？根据我需要有进一步的举动在我的应用程序。请建议或任何人可以有样本code段，请提供。

下面是code我写的：

 公共布尔contactEx​​ists（活动_activity，串号）{
    的String [] mPhoneNumberProjection = {PhoneLookup._ID，PhoneLookup.NUMBER，PhoneLookup.DISPLAY_NAME};
    。光标CUR = _activity.getContentResolver（）查询（数量，mPhoneNumberProjection，NULL，NULL，NULL）;
    尝试 {
        如果（cur.moveToFirst（））{
            返回true;
        }
    } 最后 {
        如果（CUR！= NULL）
            cur.close（）;
    }
    返回false;
} // contactEx​​ists
 

在此先感谢...

解决方案

 公共布尔contactEx​​ists（活动_activity，串号）{
    如果（数字！= NULL）{
        乌里lookupUri = Uri.withAppendedPath（PhoneLookup.CONTENT_FILTER_URI，Uri.en code（数））;
        的String [] mPhoneNumberProjection = {PhoneLookup._ID，PhoneLookup.NUMBER，PhoneLookup.DISPLAY_NAME};
        。光标CUR = _activity.getContentResolver（）查询（lookupUri，mPhoneNumberProjection，NULL，NULL，NULL）;
        尝试 {
            如果（cur.moveToFirst（））{
                返回true;
            }
        } 最后 {
            如果（CUR！= NULL）
                cur.close（）;
        }
        返回false;
    } 其他 {
        返回false;
    }
} // contactEx​​ists
 

处理的空指针异常。

I have phone number. Is there any way to check whether the phone number exists in contacts database in the device or not? Depending on that I need have move further in my app. Please suggest or if any one can have sample code snippet please provide.

The below is the code I wrote:

public boolean contactExists(Activity _activity, String number) {
    String[] mPhoneNumberProjection = { PhoneLookup._ID, PhoneLookup.NUMBER, PhoneLookup.DISPLAY_NAME };
    Cursor cur = _activity.getContentResolver().query(number, mPhoneNumberProjection, null, null, null);
    try {
        if (cur.moveToFirst()) {
            return true;
        }
    } finally {
        if (cur != null)
            cur.close();
    }
    return false;
}// contactExists

Thanks in Advance...

解决方案

public boolean contactExists(Activity _activity, String number) {
    if (number != null) {
        Uri lookupUri = Uri.withAppendedPath(PhoneLookup.CONTENT_FILTER_URI, Uri.encode(number));
        String[] mPhoneNumberProjection = { PhoneLookup._ID, PhoneLookup.NUMBER, PhoneLookup.DISPLAY_NAME };
        Cursor cur = _activity.getContentResolver().query(lookupUri, mPhoneNumberProjection, null, null, null);
        try {
            if (cur.moveToFirst()) {
                return true;
            }
        } finally {
            if (cur != null)
                cur.close();
        }
        return false;
    } else {
        return false;
    }
}// contactExists

Handled nullpointer exception.

这篇关于联系存在于接触的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！