沿其中心旋转SKShapeNode [英] Rotating an SKShapeNode along its center

问题描述

我有一个SKShapeNode（在这种情况下是矩形），我试图沿着它的中心旋转。然而，它沿着屏幕的左下角旋转。由于我无法为SKShapeNode设置锚点，我如何实现我的要求（沿着中心旋转形状）。这是我正在尝试的代码。

I have an SKShapeNode (rectangle in this case) which I am trying to rotate along its center. However it is rotating along the screen's bottom left point. Since I cannot set an anchor point for SKShapeNode, how can I achieve my requirement (to rotate the shape along its centre). This is the code I'm trying.

    let rectangle = SKShapeNode()
    rectangle.path = UIBezierPath(rect: CGRectMake(view.frame.width/4, view.frame.height/2, view.frame.width/2, view.frame.width/2)).CGPath
    rectangle.fillColor = UIColor.yellowColor()
    rectangle.strokeColor = UIColor.yellowColor()

    let oneRevolution = SKAction.rotateByAngle(360, duration: 100.0)
    let repeat = SKAction.repeatActionForever(oneRevolution)
    rectangle.runAction(repeat)

推荐答案

您是否看过SKShapeNode文档： https://developer.apple.com/library/IOs /documentation/SpriteKit/Reference/SKShapeNode_Ref/index.html

Did you look at the SKShapeNode documentation : https://developer.apple.com/library/IOs/documentation/SpriteKit/Reference/SKShapeNode_Ref/index.html

尝试使用：

shapeNodeWithPath:centered:

为居中选择YES。

如果是，则转换路径以使路径的中心位于
边界框位于节点的原点;否则路径相对于节点的原点是
。

If YES, the path is translated so that the center of the path’s bounding box is at the node’s origin; otherwise the path is relative to the node’s origin.

这篇关于沿其中心旋转SKShapeNode的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！