如何将JSON解析为Objective C - SBJSON [英] How to parse JSON into Objective C - SBJSON

问题描述

你能否告诉我如何传递一个如下所示的JSON字符串：

Could you please tell me how to pass a JSON String which looks like this:

{"lessons":[{"id":"38","fach":"D","stunde":"t1s1","user_id":"1965","timestamp":"0000-00-00 00:00:00"},{"id":"39","fach":"M","stunde":"t1s2","user_id":"1965","timestamp":"0000-00-00 00:00:00"}]}

我试过这样：

SBJSON *parser =[[SBJSON alloc] init];
    NSArray *list = [[parser objectWithString:JsonData error:nil] copy];
    [parser release];
    for (NSDictionary *stunden in list)
    {
        NSString *content = [[stunden objectForKey:@"lessons"] objectForKey:@"stunde"];

    }

提前感谢

最好的问候

推荐答案

请注意，您的JSON数据具有以下结构：

Note that your JSON data has the following structure:

1. 顶级值是一个对象（字典），它有一个名为'lessons'的属性


2. 'lessons'属性是一个数组


3. 'lessons'数组中的每个元素都是一个对象（包含课程的字典），有几个属性，包括'stunde'

相应的代码是：

SBJSON *parser = [[[SBJSON alloc] init] autorelease];
// 1. get the top level value as a dictionary
NSDictionary *jsonObject = [parser objectWithString:JsonData error:NULL];
// 2. get the lessons object as an array
NSArray *list = [jsonObject objectForKey:@"lessons"];
// 3. iterate the array; each element is a dictionary...
for (NSDictionary *lesson in list)
{
    // 3 ...that contains a string for the key "stunde"
    NSString *content = [lesson objectForKey:@"stunde"];

}

一些观察结果：

• 在 -objectWithString：错误：中，错误参数是指向指针的指针。在这种情况下，更常见的是使用 NULL 而不是 nil 。 不传递 NULL 并使用 NSError 对象来检查方法返回时出错 nil

• In -objectWithString:error:, the error parameter is a pointer to a pointer. It’s more common to use NULL instead of nil in that case. It’s also a good idea not to pass NULL and use an NSError object to inspect the error in case the method returns nil

如果 jsonObject 仅用于该特定方法，您可能不需要复制它。上面的代码没有。

If jsonObject is used only in that particular method, you probably don’t need to copy it. The code above doesn’t.

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