一周内所有NSDate的数组 [英] Array of all NSDate for a week

问题描述

我希望有一个函数，它将一个星期的数字作为输入，并返回由此特定周制作的所有NSDate的数组。

I would like to have a function that takes a week number as input and returns an array of all the NSDates that this specific week is made by.

类似于这个：

-(NSArray*)allDatesInWeek:(int)weekNumber {
    NSDate *today = [NSDate date];
    NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
    [calendar setFirstWeekday:2];
    NSDateComponents *todayComp = [calendar components:NSYearCalendarUnit fromDate:today];
    int currentyear = todayComp.year;
    /* Calculate and return the date of weekNumber for current year */

}

如何以简单的方式完成？

How can this be done in a simple way?

推荐答案

经过测试。

-(NSArray*)allDatesInWeek:(int)weekNumber {
   // determine weekday of first day of year: 
   NSCalendar *greg = [[NSCalendar alloc] 
      initWithCalendarIdentifier:NSGregorianCalendar];
   NSDateComponents *coms = [[NSDateComponents alloc] init];
   comps.day = 1;
   NSDate *today = [NSDate date];
   NSDate *tomorrow = [greg dateByAddingComponents:comps toDate:today];
   const NSTimeInterval kDay = [tomorrow timeIntervalSinceDate:today];
   comps = [greg components:NSYearCalendarUnit fromDate:[NSDate date]];
   comps.day = 1;
   comps.month = 1; 
   comps.hour = 12;
   NSDate *start = [greg dateFromComponents:comps];
   comps = [greg components:NSWeekdayCalendarUnit fromDate:start]; 
   if (weekNumber==1) {
       start = [start dateByAddingTimeInterval:-kDay*(comps.weekday-1)];
   } else {
       start = [start dateByAddingTimeInterval:
          kDay*(8-comps.weekday+7*(weekNumber-2))];
   }
   NSMutableArray *result = [NSMutableArray array];
   for (int i = 0; i<7; i++) {
       [result addObject:[start dateByAddingTimeInterval:kDay*i]];
   }
   return [NSArray arrayWithArray:result];
}

这假设一周的第一天是星期天，如NSDate所述API。如果需要调整。

This assumes the first day of the week is Sunday, as stated in the NSDate API. Tweak if desired.

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