如何只获取IP地址/子网 [英] How to get only the IP address / subnet

问题描述

我正在使用jquery插件，它会对我的字段进行屏蔽，并且只允许用户键入正确的值。它工作得很好，但现在当我提交表单时，对象IP是一个数组，我只需要检索IP号（10.1.25.2/30）

I'm using a jquery plugin, it maskered my field and allow the user only to type the correct values. It is working very well, but now when I submit my form, the object IP is an Array, I need to retrieve only the IP number (10.1.25.2/30)

结果：

$ip = $_POST['ipaddress'];
print_r($ip);

//It returns to me
Array ( [abcd] => Array ( [0] => 10.1.25.2/30 ) ) 

我需要内爆数组或以这种方式做某事......请帮忙。

I need implode the Array or do something on this way.. help please.!

整个代码：

HTML页面 jQuery插件包括：

<script src="scripts/jquery.min.js" type="text/javascript">
<script src="jquery.validate/jquery.caret.js" type="text/javascript"></script>
<script src="jquery.validate/jquery.ipaddress.js" type="text/javascript"></script>

    <script>
        $(function(){
        $('#ip').ipaddress({cidr:true});
        });     
    </script>

<form name="form1" method="post" action="equipAction.php">
 <tr>
  <td>IP</td>
  <td><input name="ipaddress[abcd][]" id="ip" type="text" value="<?=$ip;?>" />
  <b>»» IP atribuído ao contrato do Cliente/Torre </b> </td>    
 </tr>
 <input type='submit' name="alt" value="Edit" class="btn" />
</form>

现在我的动作php代码：

 if ($_POST["alt"] == "Edit") {

    # Dados do form
    $idequip  = $_GET['id'];
    $contrato = $_POST['contrato'];
    $transmi  = $_POST['transmissor'];
    $ip       = $_POST['ipaddress'];
    $local    = $_POST['local']; //tipo_equip
    $obs      = $_POST['obs'];
    $usado    = $_POST['usado'];

    echo "<br />";
    print_r($ip);




    # Atualiza dados do equipamento mestre
    # desenvolvendo
    $res = mysql_query("UPDATE equipment SET idtorre='$transmi', ip='$ip', tipo_equip='$local', obs='$obs', usado_cliente='$usado' WHERE id='$idequip'") or die("Erro na query: atualização equipamento mestre.");
    #header("Location: equipamento_adm.php?return=3&ip=$control");
    exit;
 }

全部！

推荐答案

这是一个简单的多维数组，你可以像这样检索你的值：

It a simple multidimensional array, you can retrieve your value like this :

$ip = $_POST['ipaddress'];    
$justip = $ip['abcd'][0];

现在只有 $ justip中的ip地址变量。

您应该阅读有关数组的文档： http://ch.php.net/manual/en/language.types.array.php

You should maybe read the documentation about arrays : http://ch.php.net/manual/en/language.types.array.php

这篇关于如何只获取IP地址/子网的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！