将UITableView转换为UIImageView [英] Turning a UITableView into an UIImageView

问题描述

我有一个 UITableView ，我想抓住它的可见部分，然后将它放入 UIImage 。这样做的任何方式？

I have got a UITableView, and I want to capture the visible portion of it, and put it into a UIImage. Any way of doing this?

编辑

以下自答案

推荐答案

感谢您的回复。所有答案都适用于UIView，但不适用于UITableView - 至少在表格滚动时没有。滚动时，捕获的图像将显示为黑色或透明。我尝试过类似以下的解决方案。我猜人们认为答案是显而易见的，这就是为什么我被贬低 - 因为顽皮地问这么明显的问题。

Thanks for the replies. All of the answers would work with a UIView, but not with a UITableView - at least not when the table has scrolled. When scrolled, the captured image would appear black or transparent. I had tried similar solutions as the ones below before. I guess people assumed the answer was obvious, and that's why I was down-voted - for being naughty enough to ask such an obvious question.

无论如何，真正的解决方案是您必须使用表格的contentOffset：

Anyway, the real solution is that you have to use the table's contentOffset:

- (UIImage *) imageWithTableView:(UITableView *)tableView
{
    UIView *renderedView = tableView;
    CGPoint tableContentOffset = tableView.contentOffset;
    UIGraphicsBeginImageContextWithOptions(renderedView.bounds.size, renderedView.opaque, 0.0);
    CGContextRef contextRef = UIGraphicsGetCurrentContext();
    CGContextTranslateCTM(contextRef, 0, -tableContentOffset.y);
    [tableView.layer renderInContext:contextRef];
    UIImage *image = UIGraphicsGetImageFromCurrentImageContext();
    UIGraphicsEndImageContext();
    return image;
}

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