给同一个数据参数相同的实例 [英] Giving same data parameters same instance

问题描述

我有一个具有这种结构的文本文件：

I have a text file with such structure:

{A, B, C, D}
{B, E, D}
{C, A, F}
......

第一行表示起始位置，其他行表示目的地。例如：

The first row represents a start location and the others is destinations. Forexample:

A -> B, C, D
B -> E, D
C -> A, F

我有一个名为Location的基本类，我保存所有的位置和目的地。

I have a basic class called Location, where i save all the locations and destinations.

Location locA = new Location();
Location locB = new Location();

我有兴趣使用相同的实例位置而不为每个人创建一个新实例，例如：

I'm interested in using the same instance location without making a new instance for everyone, forexample like:

Connection(locA, locB));
Connection(locA, locC));
Connection(locA, locD));
Connection(locB, locE);

问题是当我分割我的文本文件时。我把第一行放在列表中。和目的地在另一个列表中。 ：

The problem is when i'm splitting my text file. i'm putting the first row inside a list. and the destination in another list. :

DKLocations Startloc = new DKLocations();
DKLocations Destloc = new DKLocations();

List<DKLocations> DKLocations = new List<DKLocations>();

这是我的代码所以票价：

Here is my code so fare:

 foreach (var line in File.ReadLines(@"routes.txt"))
                {

                    foreach (Match oMatch in Regex.Matches(line, @"\{([^,]*)"))
                    {
                        ComboBox1.Items.Add(oMatch.Groups[1].Value);
                        Startloc.Identifier = DKLocations.Count().ToString();
                        Startloc.LocationName.Add(oMatch.Groups[1].Value);
                        DKLocations.Add(Startloc);

                        var dest = Regex.Matches(line, @"\p{L}+")
                        .Cast<Match>()
                        .Skip(1)
                        .Select(match => match.Value)
                        .ToList();

                        var price = Regex.Matches(line, @"\d+")
                        .Cast<Match>()
                        .Select(match => match.Value)
                        .ToList();

                        var destAndPrice = dest.Zip(price, (d, p) => new { dest = d, price = p });

                        foreach (var i in destAndPrice)
                        {

                            ListBox1.Items.Add(oMatch.Groups[1].Value + " to " + i.dest + " " + i.price + " kr." + DKLocations.Count().ToString());

                        }
                    }

如何为目的地提供相同的实例作为拆分时的起始位置？

How to give the destination same instance as the start location when splitting?

推荐答案

听起来你想要记忆模式。

Sounds like you want the "memoizing" pattern.

在C＃中，这通常是用字典完成的。例如：

In C#, this is usually done with a dictionary. E.g.:

Dictionary<string, Location> memos = new Dictionary<string, Location>();

然后在阅读数据时，先检查字典：

Then as you read the data, you check the dictionary first:

Location location;

if (!memos.TryGetValue(locationId, out location))
{
    location = new Location(locationId);
    memos[locationId] = location;
}

// do stuff with location now

主要的是有一种方法来识别你想要的 Location 实例，然后将其用作字典中的键。

The main thing is to have a way to identify which Location instance you want, and then use that as the key in the dictionary.

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