用Spring和杰克逊将Json阵列解析为Pojo？ [英] Parse Json Array to Pojo with Spring and Jackson?

问题描述

我有一个带有数组对象的Json字符串：

i have this Json String with an Array of Objects:

{DateFormat :[{column: 0, pattern: "yyyyMMdd"},
              {column: 2, pattern: "yyyyMMdd"} ]}

我使用Jackson Parser使用Spring MVC ..

and i user Spring MVC with the Jackson Parser..

Java Pojo看起来如何能够将这个Json String自动解析为Object？

How must the Java Pojo looks like that i can parse this Json String automaticly to an Object ?

在Spring我通常会这样做：

in Spring i do it normally like this:

public @ResponseBody String login(@RequestBody DateFormat dataFormaPojo){

}

这适用于简单的Json字符串但是我怎样才能将我的对象数组解析为Java对象或带有对象的ArrayList？我希望Jackson解析器在收到json文件时自动处理它。

this works for an easy Json String but how can i parse my Array of Objects to an Java Object or to an ArrayList with Objects in it? I want that the Jackson parser handles this automaticly if it recieves the json file.

编辑：我已经扩展了json文件，创建了这个java类，但它没有工作：

i have extended the json file a little an created this java classes but it didn`t work:

import java.io.Serializable;
public class DataFormat implements Serializable
{
    private static
    final long serialVersionUID = 1L;
    private Integer column;
    private String type;
    private String pattern;
    public Integer getColumn()
    {
        return column;
    }
    public void setColumn(Integer column)
    {
        this.column = column;
    }
    public String getType()
    {
        return type;
    }
    public void setType(String type)
    {
        this.type = type;
    }
    public String getPattern()
    {
        return pattern;
    }
    public void setPattern(String pattern)
    {
        this.pattern = pattern;
    }
}

和DataFormList类

And the DataFormList class

import java.io.Serializable;
import java.util.ArrayList;
import
java.util.List;
public class DataFormatList implements Serializable
{
    private static final long serialVersionUID = 2514719982327593095L;
    private List<DataFormat> DataFormat = new ArrayList<DataFormat> ();
    public List<DataFormat>  getDateFormats()
    {
        return DataFormat;
    }
    public void setDateFormats(List<DataFormat> formats)
    {
        this.DataFormat= formats;
    }
}

和Spring：

@RequestMapping(value="/save",method=
{
    RequestMethod.GET,RequestMethod.POST
}
)
public @ResponseBody String createDataSource( @RequestBody DataFormatList dataFormaPojo)
{
    for(DataFormat df: dataFormaPojo.getDateFormats())
    {
        System.out.println(df.getType());
    }
    return "";
}

我得到的Json字符串如下所示：

The Json String that i gett looks like this:

{
    "DataFormat": [
        {
            "column": 0,
            "type": "number"
        },
        {
            "column": 1,
            "type": "number"
        },
        {
            "column": 2,
            "type": "number"
        },
        {
            "column": 3,
            "type": "number"
        }
    ]
}

我可以设置自定义名称如果我想要对象 DataFormat 有另一个名字？对于带杰克逊的对象？

Can I set a custom name for the Objects with Jackson if i want that that the Object DataFormat has an other name ?

为什么我的class不解析json字符串？我没有收到任何错误消息。

and why did my class not parse the json string ? i got no error message.

EDIT3：如果我查看goolge chrome dev工具我得到400 Bad Request Message但是在Spring我没有收到错误来自Jackson的消息他无法将我的数据解析为Pojo ..

if i look in the goolge chrome dev tool i get a 400 Bad Request Message but in Spring i get no error Message from Jackson that he can not parse my Data to a Pojo..

推荐答案

用户对象映射器获取具有相应json字符串的java类的对象

user object mapper to get object of java class with corresponding json string

对象映射器的java文档

这里的示例可能对您有帮助
在此输入链接说明

这篇关于用Spring和杰克逊将Json阵列解析为Pojo？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！