Ajax测试代码抛出错误 [英] Ajax test code throwing error

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本文介绍了Ajax测试代码抛出错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在使用jasmine测试代码并为ajax方法创建模拟对象

I am testing a code using jasmine and creating a mock object for ajax method

spyOn($,'ajax').and.callFake(function(e){
console.log("is hitting");
})

来测试以下代码

$.ajax({
               url: AppManager.defaults.contextPath + "/solutions/mcn/mcn-lookup-list",
               data: {
                    mcnNumber       : mcnNumberData,
                    mcnCustomerName : mcnCustomerNameData
               },
               dataType: "json",
               type: "GET",
               global: false
        })
        .done(function(data) {
               solution.CommonObjects.theSolution.orderHandoff.mcnSearchData = self.filterMCNSearchData(data, resultObj);
               $promise.resolve();
        })
        .fail(function() {
             $promise.reject();
             self.displayErrorPopup('MCN Search Error','There is no MCN associated with MCN Number or MCN Customer Name Entered!!!');
        });
    },

抛出错误无法读取未定义的内容。我是否也需要为此创建一个间谍。请帮助我们执行此操作

It's throwing an error cannot read done of undefined . Do I need to create a spy for that also . Please help with the code to do so

推荐答案

您的代码问题:


  • 你正在监视它,但是你需要通过你的间谍回复 promise 对象。基本上你需要返回这样的东西==> 返回新的$ .Deferred()。resolve(dummyData).promise();

  • 有多种方法可以创建延迟对象/承诺对象。我建议你阅读 承诺 & 延期

  • 您还可以解释一下 $ promise 的来源吗?这是 require.js的一些功能

  • You are spying it right but you need to send in a promise object back via your spy. Basically you need to return something like this ==> return new $.Deferred().resolve(dummyData).promise();
  • There are multiple ways to create a deferred object/promise object. I suggest you to read both Promise & Deferred
  • Also could you explain where your $promise is coming from? is this some feature of require.js?

以下是一种方法伪造ajax调用。

Below is one way to fake the ajax calls.

var testObj = {
    ajaxFunction: function() {
      $.ajax({
        url: 'https://jsonplaceholder.typicode.com/posts/1'
      }).done(function(data){
        consoleLogFunction(data);
      });
    }
};

var consoleLogFunction = function(data){
    console.log("The lengh of array is..=> "+ data.length);
};

describe("ajax test suite", function() {
  it("expect true to be true", function() {
    var dummyData = ["Foo", "Boo"];
    spyOn($, 'ajax').and.callFake(function(e){
      return new $.Deferred().resolve(dummyData).promise();
    });
    spyOn(window, 'consoleLogFunction').and.callThrough();
    testObj.ajaxFunction();
    expect(window.consoleLogFunction).toHaveBeenCalledWith(dummyData);
  });
});

这篇关于Ajax测试代码抛出错误的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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