ajax抛出错误与正确的结果 [英] ajax throwing error with right outcome
问题描述
我有以下功能：
side ='car';
var request_checkUrl ='/ antibot / antibot_data？script ='+ side;
$ .ajax（{
url：request_checkUrl，
dataType：'application / json'，
complete：function（data）{
alert running ..）;
}，
success：function（data）{
alert（success）;
}，
error：function ）{
alert（ERROR）;
console.log（data）;
}
}）
结果是：
该框有ERROR，并且正在运行。它也会在控制台日志中显示：
回应正确。
我也尝试过get，getjson，ajax和数据类型json等。但是，为什么这段代码会抛出错误信息，但我得到了相同的结果。
我在这里做了什么错误？
这里是完整的回应：
{
status： 200，
data：{
text：en TV，
images：[
{
hash：47a32df0c4b1f0b522e5faf35a46aacd95fe0ed4，
file：ABImage_plane_1
}，
{
hash：e11f83f4411364546329c8a8bf88da0dffd27029，
file：ABImage_house_2
} ，
{
hash：93b4454ac09e7d7478fa2d25322e0e784370ea7a，
file：ABImage_car_5
}，
{
hash：36fac21a830b922edb507487d833556aeb9688f7 ，
file：ABImage_clock_4
}，
{
hash：cd1df47e052a5d0d50dab61b3e716339be0c6e68，
file：ABImage_TV_3 b}，
{
hash：59e7f70b7874a500e576e25077adf254c52f5ee8，
file：ABImage_train_4
}
]
}
}
EDIT2：
函数，使用服务器端PHP
echo $ this-> framework-> ajaxJSONResponse（200，$ data）;
和
function ajaxJSONResponse（$ status，$ data）{
header（'Content-type：application / json'）;
$ response = array（）;
$ response ['status'] = $ status;
$ response ['data'] = $ data;
return json_encode（$ response）;
}
编辑：
im使用jquery 2.1.3
< script src =// cdnjs.cloudflare.com/ajax/libs/jquery/2.1.3/jquery.min.js >< / script>
编辑：
我也试过：
$。ajax（{
url：request_checkUrl，
type：GET，
dataType：json，//xml ，json
success：function（data）{
alert（success）;
alert（data）;
}
error：function（jqXHR，textStatus，ex）{
alert（textStatus +，+ ex +，+ jqXHR.responseText）;
}
}
输出错误：
a href =https://i.stack.imgur.com/frlXc.png =nofollow noreferrer>
更新时间：
我尝试验证网址：
http://www.freeformatter.com/json-validator.html
并获得：
JSON输入无效根据RFC 4627（JSON规范）。意外的令牌{status：200，data：{text：en TV，images：[{hash：47a32df0c4b1f0b522e5faf35a46aacd95fe0ed4，file：ABImage_plane_1}，...
但如果我启用：
接受未引用的名称
我获得：
JSON输入根据RFC 4627（JSON规范）有效。
如何使我的请求也能工作？
尝试将您的代码修改为类似于下面的代码： this：
var side ='car';
var request_checkUrl ='/ antibot / antibot_data？script ='+ side;
$ .ajax（{
url：request_checkUrl，
type：GET，
dataType：'json'，
beforeSend：function {
document.title =Running ...;
}，
success：function（data）{
document.title =Success。;
alert（success）;
}，
错误：function（data）{
alert（ERROR）;
console.log（data）;
}
}）;
让我知道这是否有效。
更新：
在上次更新时，您将收到无效的json。因为PHP你需要打印一个有效的json，总是。您可以使用此链接验证您的json输出： http://pro.jsonlint.com 。
parsererror，SintaxError：意外的令牌：这意味着你在PHP代码中有错误。
I have the following function:
side= 'car';
var request_checkUrl = '/antibot/antibot_data?script=' + side;
$.ajax({
url: request_checkUrl,
dataType: 'application/json',
complete: function(data){
alert("running..");
},
success: function(data){
alert("success");
},
error: function(data) {
alert("ERROR");
console.log(data);
}
})
the results are: the box with ERROR, and the running. it also shows this in the console log:
tthe response is correct. but, why does this piece of code throw me error message, when it should be success?
I also tried with get, getjson, ajax with datatype json, etc.. but i get the same outcome.
What have i done wrong here?
EDIT:
here is the full response:
{
"status": 200,
"data": {
"text": "en TV",
"images": [
{
"hash": "47a32df0c4b1f0b522e5faf35a46aacd95fe0ed4",
"file": "ABImage_plane_1"
},
{
"hash": "e11f83f4411364546329c8a8bf88da0dffd27029",
"file": "ABImage_house_2"
},
{
"hash": "93b4454ac09e7d7478fa2d25322e0e784370ea7a",
"file": "ABImage_car_5"
},
{
"hash": "36fac21a830b922edb507487d833556aeb9688f7",
"file": "ABImage_clock_4"
},
{
"hash": "cd1df47e052a5d0d50dab61b3e716339be0c6e68",
"file": "ABImage_TV_3"
},
{
"hash": "59e7f70b7874a500e576e25077adf254c52f5ee8",
"file": "ABImage_train_4"
}
]
}
}
EDIT2:
this is the function that im using server sided PHP
echo $this->framework->ajaxJSONResponse(200, $data);
and
function ajaxJSONResponse($status, $data) {
header('Content-type: application/json');
$response = array();
$response['status'] = $status;
$response['data'] = $data;
return json_encode($response);
}
EDIT: im using jquery 2.1.3
<script src="//cdnjs.cloudflare.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
EDIT: I also tried:
$.ajax({
url: request_checkUrl,
type: "GET",
dataType: "json", // "xml", "json"
success: function (data) {
alert("success");
alert(data);
},
error: function (jqXHR, textStatus, ex) {
alert(textStatus + "," + ex + "," + jqXHR.responseText);
}
});
with the output error:
UPDATE AGAIN:
i tried to validate url with: http://www.freeformatter.com/json-validator.html
and got:
The JSON input is NOT valid according to RFC 4627 (JSON specification). Unexpected token {"status":200,"data":{"text":"en TV","images":[{"hash":"47a32df0c4b1f0b522e5faf35a46aacd95fe0ed4","file":"ABImage_plane_1"},...
but if i enable:
Accept non-quoted names
i get :
The JSON input is valid according to RFC 4627 (JSON specfication).
how can i make this work on my request too?
The following answer just try to help with a possible solution.
Try to fix your code to something like this:
var side = 'car';
var request_checkUrl = '/antibot/antibot_data?script=' + side;
$.ajax({
url: request_checkUrl,
type: "GET",
dataType: 'json',
beforeSend: function () {
document.title = "Running...";
},
success: function (data) {
document.title = "Success.";
alert("success");
},
error: function (data) {
alert("ERROR");
console.log(data);
}
});
Let me know if this works.
Update:
In your last update, you are getting an invalid json. Since PHP you need to print a valid json, always. You might use this link to validate your json output: http://pro.jsonlint.com.
parsererror, SintaxError: Unexpected token: It means, you've something wrong in php code.
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