Android的：如何排序数据的ListView？ [英] Android: How to sort data for ListView?
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问题描述
我有一些JSON数据，我从一台服务器拉下。一个在此数据字段是一个距离值。我需要有数据按距离排序从低到高在ListView。我不知道如何去这样做呢？
任何帮助AP preciated。
这是我的code来获取数据不知道如何得到它的排序是否正确？
//哈希映射为的ListView
ArrayList的＆LT; HashMap的＆LT;字符串，字符串＆GT;＆GT; bathroomList =新的ArrayList＆LT; HashMap的＆LT;字符串，字符串＆GT;＆GT;（）;
@覆盖
公共无效的onCreate（包savedInstanceState）{
super.onCreate（savedInstanceState）;
requestWindowFeature（Window.FEATURE_CUSTOM_TITLE）;
的setContentView（R.layout.activity_search）;
。getWindow（）setFeatureInt（Window.FEATURE_CUSTOM_TITLE，R.layout.window_title）;
//创建JSON解析器实例
JSONParser jParser =新JSONParser（）;
//从URL获取JSON字符串
JSONObject的JSON = jParser.getJSONFromUrl（URL）;
尝试 {
//获取联系人的数组
浴室= json.getJSONArray（TAG_BATHROOMS）;
//遍历所有联系人
的for（int i = 0; I＆LT; bathrooms.length（）;我++）{
JSONObject的C = bathrooms.getJSONObject（我）;
//保存在变量中的每个JSON项目
字符串ID = c.getString（TAG_ID）;
串访问= c.getString（TAG_ACCESS）;
字符串的城市= c.getString（TAG_CITY）;
字符串注释= c.getString（TAG_COMMENT）;
字符串方向= c.getString（TAG_DIRECTIONS）;
字符串名称= c.getString（TAG_NAME）;
串街道= c.getString（TAG_STREET）;
字符串bathroomtype = c.getString（TAG_BATHROOMTYPE）;
字符串距离= c.getString（TAG_DISTANCE）;
字符串distanceTrimmed = distance.substring（0,4）++英里远;
串果= c.getString（TAG_AVAIL）;
字符串全国= c.getString（TAG_COUNTRY）;
字符串状态= c.getString（TAG_STATE）;
字符串邮政= c.getString（TAG_POSTAL）;
//System.out.println(name）;
//创建新的HashMap
HashMap的＆LT;字符串，字符串＆GT;图=新的HashMap＆LT;字符串，字符串＆GT;（）;
//添加每个子节点HashMap中的key =＆GT;值
map.put（tag_id，分别编号）;
map.put（TAG_ACCESS，访问）;
map.put（TAG_CITY，市）;
map.put（TAG_COMMENT，评论）;
map.put（TAG_DIRECTIONS，方向）;
map.put（TAG_NAME，姓名）;
map.put（TAG_STREET，街道）;
map.put（TAG_BATHROOMTYPE，bathroomtype）;
map.put（TAG_DISTANCE，distanceTrimmed）;
map.put（TAG_AVAIL，无济于事）;
map.put（TAG_COUNTRY，国家）;
map.put（TAG_STATE，状态）;
map.put（TAG_POSTAL，邮政）;
//添加HashList到ArrayList中
bathroomList.add（图）
}
}赶上（JSONException E）{
e.printStackTrace（）;
}
/ **
*更新解析JSON数据到ListView控件
* * /
ListAdapter适配器=新SimpleAdapter（这一点，bathroomList，
R.layout.list_item，
新的String [] {tag_id，分别TAG_NAME，TAG_STREET，TAG_CITY，TAG_STATE，TAG_POSTAL，TAG_COUNTRY，TAG_DISTANCE，TAG_DIRECTIONS，TAG_COMMENT，TAG_AVAIL，TAG_BATHROOMTYPE，TAG_ACCESS}，新的INT [] {
R.id.key，R.id.name，R.id.street，R.id.city，R.id.state，R.id.postal，R.id.country，R.id.distance，R。 id.directions，R.id.comments，R.id.availability，R.id.bathroomtype，R.id.access}）;
setListAdapter（适配器）;
解决方案
使用排序列表<一href="http://docs.oracle.com/javase/7/docs/api/java/util/Collections.html#sort%28java.util.List,%20java.util.Comparator%29"相对=nofollow> Collections.sort（）用自定义的比较。
Collections.sort（bathroomList，新的比较＆LT; HashMap的＆LT;字符串，字符串＆GT;＆GT;（）
{
@覆盖
公众诠释比较（HashMap的＆LT;字符串，字符串＆gt;将一个HashMap＆LT;字符串，字符串＆GT; B）
{
返回a.get（TAG_DISTANCE）.compareTo（b.get（TAG_DISTANCE））;
}
}）;
I have some JSON data I am pulling down from a server. One of the fields in this data is a distance value. I need to have the data sorted by distance from lowest to highest in the ListView. I am not sure how to go about doing this?
Any help appreciated.
This is my code to grab the data not sure how to get it sorted properly?
// Hashmap for ListView
ArrayList<HashMap<String, String>> bathroomList = new ArrayList<HashMap<String, String>>();
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
requestWindowFeature(Window.FEATURE_CUSTOM_TITLE);
setContentView(R.layout.activity_search);
getWindow().setFeatureInt(Window.FEATURE_CUSTOM_TITLE, R.layout.window_title);
// Creating JSON Parser instance
JSONParser jParser = new JSONParser();
// getting JSON string from URL
JSONObject json = jParser.getJSONFromUrl(url);
try {
// Getting Array of Contacts
bathrooms = json.getJSONArray(TAG_BATHROOMS);
// looping through All Contacts
for(int i = 0; i < bathrooms.length(); i++){
JSONObject c = bathrooms.getJSONObject(i);
// Storing each json item in variable
String id = c.getString(TAG_ID);
String access = c.getString(TAG_ACCESS);
String city = c.getString(TAG_CITY);
String comment = c.getString(TAG_COMMENT);
String directions = c.getString(TAG_DIRECTIONS);
String name = c.getString(TAG_NAME);
String street = c.getString(TAG_STREET);
String bathroomtype = c.getString(TAG_BATHROOMTYPE);
String distance = c.getString(TAG_DISTANCE);
String distanceTrimmed = distance.substring(0,4) + " " + "miles away";
String avail = c.getString(TAG_AVAIL);
String country = c.getString(TAG_COUNTRY);
String state = c.getString(TAG_STATE);
String postal = c.getString(TAG_POSTAL);
//System.out.println(name);
// creating new HashMap
HashMap<String, String> map = new HashMap<String, String>();
// adding each child node to HashMap key => value
map.put(TAG_ID, id);
map.put(TAG_ACCESS, access);
map.put(TAG_CITY, city);
map.put(TAG_COMMENT, comment);
map.put(TAG_DIRECTIONS, directions);
map.put(TAG_NAME, name);
map.put(TAG_STREET, street);
map.put(TAG_BATHROOMTYPE, bathroomtype);
map.put(TAG_DISTANCE, distanceTrimmed);
map.put(TAG_AVAIL, avail);
map.put(TAG_COUNTRY, country);
map.put(TAG_STATE, state);
map.put(TAG_POSTAL, postal);
// adding HashList to ArrayList
bathroomList.add(map);
}
} catch (JSONException e) {
e.printStackTrace();
}
/**
* Updating parsed JSON data into ListView
* */
ListAdapter adapter = new SimpleAdapter(this, bathroomList,
R.layout.list_item,
new String[] { TAG_ID, TAG_NAME, TAG_STREET, TAG_CITY, TAG_STATE, TAG_POSTAL,TAG_COUNTRY, TAG_DISTANCE, TAG_DIRECTIONS, TAG_COMMENT, TAG_AVAIL, TAG_BATHROOMTYPE, TAG_ACCESS}, new int[] {
R.id.key,R.id.name, R.id.street, R.id.city, R.id.state, R.id.postal,R.id.country, R.id.distance, R.id.directions, R.id.comments, R.id.availability, R.id.bathroomtype, R.id.access });
setListAdapter(adapter);
解决方案
Sort the list using Collections.sort() with a custom comparator.
Collections.sort(bathroomList, new Comparator<HashMap<String, String>>()
{
@Override
public int compare(HashMap<String, String> a, HashMap<String, String> b)
{
return a.get(TAG_DISTANCE).compareTo(b.get(TAG_DISTANCE));
}
});
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