是否可以以编程方式配置JAXB？ [英] Is it possible to programmatically configure JAXB?
问题描述
假设我有两个JavaBeans 人和地址。
Say I have two JavaBeans Person and Address.
如果我创建一个Person对象列表，我想编组这样的东西：
If I create a list of Person objects, I'd like to marshal to something like this:
<persons>
<person>...</person>
</persons>
可以使用此处描述的技术：
使用JAXB解组/编组列表< String>
It's possible to use the technique described here: Using JAXB to unmarshal/marshal a List<String>
使用 @XmlRootElement（name =persons）和 @XmlElement（name =person），然后可以编组上面的XML。
By annotating JaxbList with @XmlRootElement(name = "persons") and @XmlElement(name = "person"), then it's possible to marshal to the XML above.
但是，能够重复使用相同的 JaxbList< T> 类来编组也很好地址对象的列表。实际上，我会有很多其他类型的豆子。我可以使用以下内容：
But, it'd be nice to be able to reuse the same JaxbList<T> class to also marshal a list of Address objects. And in reality, I will have many other types of beans. I can go with something like:
<list>
<item xsi:type="person" xmlns:xsi="http://www.w2.org/2001/XmlSchema-instance"></item>
</list>
但理想情况下，将复制版本替换为list会很好类名和带有类名的item。
But, ideally, it'd be nice to have it replace "list" with the plural version of class name and "item" with the class name.
那么，是否可以在运行时以编程方式配置JaxbContext或其他东西，并基本上设置 name的值在 @XmlRootElement 和 @XmlElement ？
So, is it possible to programmatically configure the JaxbContext or something during runtime and essentially set the value of the name inside @XmlRootElement and @XmlElement?
或任何其他方法让这个工作，而不必为每个bean类型编写 JaxbList 的单独实现？也许XmlJavaTypeAdapter可以做到这一点？
Or any other way to get this working without having to write a separate implementation of JaxbList for every bean type? Maybe XmlJavaTypeAdapter can achieve this sort of thing?
更新
@Blaise Doughan在下面接受的解决方案效果很好。对于我的用例，我需要直接从Java对象到XML，这里有用（注意这不是我的完整实现，它只是用于演示的伪代码）：
Update @Blaise Doughan's solution accepted below works great. For my use case, I needed to go straight from Java object to XML, here's what worked (note this is not my full implementation, it's sort of just pseudo code for demonstration):
//JAXBContext is thread safe and so create it in constructor or
//setter or wherever:
...
JAXBContext jc = JAXBContext.newInstance(Wrapper.class, clazz);
...
public String marshal(List<T> things, Class clazz) {
//configure JAXB and marshaller
Marshaller m = jc.createMarshaller();
m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
//Create wrapper based on generic list of objects
Wrapper<T> wrapper = new Wrapper<T>(things);
JAXBElement<Wrapper> wrapperJAXBElement = new JAXBElement<Wrapper>(new QName(clazz.getSimpleName().toLowerCase()+"s"), Wrapper.class, wrapper);
StringWriter result = new StringWriter();
//marshal!
m.marshal(wrapperJAXBElement, result);
return result.toString();
}
推荐答案
你可以创建一个通用的 Wrapper 对象，如下所示：
You could create a generic Wrapper object like the following:
Wrapper
您可以创建一个通用包装类，其中 List 属性用 @XmlAnyElement注释（lax = true）。用于填充此列表的对象类型将基于其根元素（请参阅： http://blog.bdoughan.com/2010/08/using-xmlanyelement-to-build-generic.html ）。
You could create a generic wrapper class with a List property annotated with @XmlAnyElement(lax=true). The type of the object used to populate this list will be based on its root element (see: http://blog.bdoughan.com/2010/08/using-xmlanyelement-to-build-generic.html).
package forum13272288;
import java.util.*;
import javax.xml.bind.annotation.XmlAnyElement;
public class Wrapper<T> {
private List<T> items = new ArrayList<T>();
@XmlAnyElement(lax=true)
public List<T> getItems() {
return items;
}
}
地址
您需要使用 @XmlRootElement 注释列表中可能的内容。
You will need to annotate the possible contents of the list with @XmlRootElement.
package forum13272288;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class Address {
}
人
package forum13272288;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class Person {
}
演示
下面的演示代码演示了如何使用 Wrapper 上课。由于根元素可以不同，因此您需要指定要对包装类进行解组。或者，您可以利用 @XmlElementDecl 批注将多个根元素与包装类关联（请参阅： http://blog.bdoughan.com/2012/07/jaxb-and-root-elements.html 。
The demo code below demonstrates how to use the Wrapper class. Since the root element can be different you will need to specify that you want to unmarshal to the wrapper class. Alternatively you could leverage the @XmlElementDecl annotation to associate multiple root elements with the wrapper class (see: http://blog.bdoughan.com/2012/07/jaxb-and-root-elements.html).
package forum13272288;
import javax.xml.bind.*;
import javax.xml.transform.stream.StreamSource;
public class Demo {
public static void main(String[] args) throws Exception {
JAXBContext jc = JAXBContext.newInstance(Wrapper.class, Person.class, Address.class);
Unmarshaller unmarshaller = jc.createUnmarshaller();
Marshaller marshaller = jc.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
StreamSource personsXML = new StreamSource("src/forum13272288/persons.xml");
JAXBElement<Wrapper> wrapper1 = unmarshaller.unmarshal(personsXML, Wrapper.class);
marshaller.marshal(wrapper1, System.out);
StreamSource addressesXML = new StreamSource("src/forum13272288/addresses.xml");
JAXBElement<Wrapper> wrapper2 = unmarshaller.unmarshal(addressesXML, Wrapper.class);
marshaller.marshal(wrapper2, System.out);
}
}
输出
以下是运行演示代码的输出。文件 persons.xml 和 addresses.xml 看起来就像有相应的输出。
Below is the output from running the demo code. The files persons.xml and addresses.xml look just like there corresponding output.
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<persons>
<person/>
<person/>
</persons>
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<addresses>
<address/>
<address/>
</addresses>
更多信息
- http://blog.bdoughan.com/2012/11/creating-generic-list-wrapper-in-jaxb.html
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