在Java中对单个String进行排序 [英] Sort a single String in Java

问题描述

是否有一种本地方法可以通过java中的内容对String进行排序？例如。

Is there a native way to sort a String by its contents in java? E.g.

String s = "edcba"  ->  "abcde"

推荐答案

toCharArray 后跟 Arrays.sort 后跟一个String构造函数调用：

toCharArray followed by Arrays.sort followed by a String constructor call:

import java.util.Arrays;

public class Test
{
    public static void main(String[] args)
    {
        String original = "edcba";
        char[] chars = original.toCharArray();
        Arrays.sort(chars);
        String sorted = new String(chars);
        System.out.println(sorted);
    }
}

编辑：正如指标所指出的那样，如果该字符串包含代理对或确实是复合字符（重音+ e作为单独的字符）等等。此时它变得更难...希望你不需要这个:)此外，这只是顺序排序，没有考虑大写，重音或其他任何因素。

As tackline points out, this will fail if the string contains surrogate pairs or indeed composite characters (accent + e as separate chars) etc. At that point it gets a lot harder... hopefully you don't need this :) In addition, this is just ordering by ordinal, without taking capitalisation, accents or anything else into account.

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