是否有可能解除Spring bean的问题？ [英] Is it possible to unproxy a Spring bean?

问题描述

我有一个Spring bean，让我们说：

I have a Spring bean, let's say:

@TransactionAttribute(TransactionAttributeType.REQUIRED) 
public class AImpl implements A {

     public void setSomeDependency(D dependency) {
         // This setter DOES NOT BELONG to interface A
     }
}

<bean id="aImpl" class="AImpl"/>

现在我想集成测试它，但首先我需要模拟依赖项 D ，因为它做的太多了。由于 AImpl 实现了一个接口并包含一个事务注释，因此生成的代理只与接口 A 兼容，所以我可以这样做：

Now I want to integration test it, but first I need to mock the dependency D, because it does too much stuff. Since the AImpl implements an interface and contains a transactional annotation, the generated proxy is only compatible with the interface A, so I can do this:

@Inject @Named("aImpl")
private A a;

但不能：

@Inject @Named("aImpl")
private AImpl a;

因此，我无法模仿我的依赖。

As a result, I can't mock my dependency.

请注意，将 void setSomeDependency（D dependency）添加到接口 A 不是一个选项，因为它没有商业意义。它既不使用 proxy-target-class =true，因为它会破坏很多其他bean（此属性会影响上下文中的所有bean）。

Please note that adding void setSomeDependency(D dependency) to interface A is not an option, as it has no business meaning. Neither it is using the proxy-target-class="true", as it breaks a whole lot of other beans (this attribute affects all beans in the context).

有没有办法取消注入注入的bean A ，所以我可以将它转换为 AImpl ？

Is there a way to unproxy the injected bean A, so I could cast it to AImpl?

推荐答案

试试这个：

if(AopUtils.isAopProxy(a) && a instanceof Advised) {
    Object target = ((Advised)a).getTargetSource().getTarget();
    AImpl ai = (AImpl)target;
}

奖励：在Scala中我使用以下等效函数用于同一目的：

Bonus: in Scala I am using the following equivalent function for the very same purpose:

def unwrapProxy(a: AnyRef) = a match {
    case advised: Advised if(AopUtils.isAopProxy(advised)) => 
                            advised.getTargetSource.getTarget
    case notProxy => notProxy
}

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