检查字符串是否以某种模式结束 [英] check if string ends with certain pattern

问题描述

如果我有一个字符串：

This.is.a.great.place.too.work.

或：

This/is/a/great/place/too/work/

比我的程序应该告诉我这句话是有效的并且它有工作。

than my program should give me that the sentence is valid and it has "work".

如果我有：

This.is.a.great.place.too.work.hahahha

或：

This/is/a/great/place/too/work/hahahah

然后我的程序不应该告诉我句子中有工作。

then my program should not give me that there is a "work" in the sentence.

所以我正在查看java字符串，以便在。或，或 / 在它之前。我怎样才能做到这一点？

So I am looking at java strings to find a word at the end of the sentance having ., or , or / before it. How can I achieve this?

推荐答案

这很简单， String 对象有 endsWith 方法。

This is really simple, the String object has an endsWith method.

从您的问题看来，您似乎想要 / ，，或。作为分隔符集。

From your question it seems like you want either /, , or . as the delimiter set.

所以：

String str = "This.is.a.great.place.to.work.";

if (str.endsWith(".work.") || str.endsWith("/work/") || str.endsWith(",work,"))
     // ... 

您也可以使用 匹配 方法和一个相当简单的正则表达式：

You can also do this with the matches method and a fairly simple regex:

if (str.matches(".*([.,/])work\\1$"))

使用字符类 [。，/ ] 指定一个句点，一个斜杠或一个逗号，以及一个反向引用， \1 匹配任何一个替换项，如果找到，任何。

Using the character class [.,/] specifying either a period, a slash, or a comma, and a backreference, \1 that matches whichever of the alternates were found, if any.

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