在String中查找重复字符并使用Java计算出现次数 [英] Find duplicate characters in a String and count the number of occurances using Java

问题描述

如何找到字符串中字符的出现次数？

How can I find the number of occurrences of a character in a string?

例如：快速的棕色狐狸跳过懒狗

For example: The quick brown fox jumped over the lazy dog.

下面是一些示例输出，

'a' = 1
'o' = 4
'space' = 8
'.' = 1

推荐答案

import java.io.*;
public class CountChar 
{

    public static void main(String[] args) throws IOException
    {
      String ch;
      BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
      System.out.print("Enter the Statement:");
      ch=br.readLine();
      int count=0,len=0;
        do
        {  
          try
          {
          char name[]=ch.toCharArray();
              len=name.length;
              count=0;
              for(int j=0;j<len;j++)
               {
                  if((name[0]==name[j])&&((name[0]>=65&&name[0]<=91)||(name[0]>=97&&name[0]<=123))) 
                      count++;
               }
              if(count!=0)
                System.out.println(name[0]+" "+count+" Times");
              ch=ch.replace(""+name[0],"");          
          }
          catch(Exception ex){}
        }
        while(len!=1);
   }

}

输出

Enter the Statement:asdf23123sfsdf

a 1 Times

s 3 Times

d 2 Times

f 3 Times

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