为什么这个Java程序占用了这么多内存？ [英] Why is this Java program taking up so much memory?

问题描述

我有一小段代码，每五分钟就会截取一次我的桌面屏幕截图 - 这是一个轻松思考的工作，并计算出多少截图，比如facebook ...

I have a small piece of code that takes a screenshot of my desktop every five minutes - it's the work of a moment to flick thought and work out how many screenshots are of, say, facebook...

然而，我对它占用的内存量感到有点困惑 - 通常它会爬升到200mb的RAM，我相信这是多余的......有谁能告诉我a）减少内存占用的明智方法或b）为什么上升？

However I'm a little confused by the amount of memory it takes up - often it will creep up to 200mb of RAM, which I'm sure is excessive... Can anyone tell me a) sensible ways to reduce the memory footprint or b) why it's going up at all?

/**
 * Code modified from code given in http://whileonefork.blogspot.co.uk/2011/02/java-multi-monitor-screenshots.html following a SE question at  
 * http://stackoverflow.com/questions/10042086/screen-capture-in-java-not-capturing-whole-screen and then modified by a code review at http://codereview.stackexchange.com/questions/10783/java-screengrab
 */
package com.tmc.personal;

import java.awt.AWTException;
import java.awt.GraphicsDevice;
import java.awt.GraphicsEnvironment;
import java.awt.Rectangle;
import java.awt.Robot;
import java.awt.image.BufferedImage;
import java.io.File;
import java.io.IOException;
import java.text.DateFormat;
import java.text.SimpleDateFormat;
import java.util.Date;
import java.util.TimeZone;
import java.util.concurrent.TimeUnit;

import javax.imageio.ImageIO;

class ScreenCapture {

    static int minsBetweenScreenshots = 5;

    public static void main(String args[]) {
        int indexOfPicture = 1000;// should be only used for naming file...
        while (true) {
            takeScreenshot("ScreenCapture" + indexOfPicture++);
            try {
                TimeUnit.MINUTES.sleep(minsBetweenScreenshots);
            } catch (Exception e) {
                e.printStackTrace();
            }
        }
    }

    //from http://www.coderanch.com/t/409980/java/java/append-file-timestamp
    private  final static String getDateTime()
    {
        DateFormat df = new SimpleDateFormat("yyyy-MM-dd_hh:mm:ss");
        df.setTimeZone(TimeZone.getTimeZone("PST"));
        return df.format(new Date());
    }

    public static void takeScreenshot(String filename) {
        Rectangle allScreenBounds = getAllScreenBounds();
        Robot robot;
        try {
            robot = new Robot();
            BufferedImage screenShot = robot.createScreenCapture(allScreenBounds);
            ImageIO.write(screenShot, "jpg", new File(filename + getDateTime()+ ".jpg"));
        } catch (AWTException e) {
            System.err.println("Something went wrong starting the robot");
            e.printStackTrace();
        } catch (IOException e) {
            System.err.println("Something went wrong writing files");
            e.printStackTrace();
        }
    }

    /**
     * Okay so all we have to do here is find the screen with the lowest x, the
     * screen with the lowest y, the screen with the higtest value of X+ width
     * and the screen with the highest value of Y+height
     * 
     * @return A rectangle that covers the all screens that might be nearby...
     */
    private static Rectangle getAllScreenBounds() {
        Rectangle allScreenBounds = new Rectangle();
        GraphicsEnvironment ge = GraphicsEnvironment.getLocalGraphicsEnvironment();
        GraphicsDevice[] screens = ge.getScreenDevices();

        int farx = 0;
        int fary = 0;
        for (GraphicsDevice screen : screens) {
            Rectangle screenBounds = screen.getDefaultConfiguration().getBounds();
            // finding the one corner
            if (allScreenBounds.x > screenBounds.x) {
                allScreenBounds.x = screenBounds.x;
            }
            if (allScreenBounds.y > screenBounds.y) {
                allScreenBounds.y = screenBounds.y;
            }
            // finding the other corner
            if (farx < (screenBounds.x + screenBounds.width)) {
                farx = screenBounds.x + screenBounds.width;
            }
            if (fary < (screenBounds.y + screenBounds.height)) {
                fary = screenBounds.y + screenBounds.height;
            }
            allScreenBounds.width = farx - allScreenBounds.x;
            allScreenBounds.height = fary - allScreenBounds.y;
        }
        return allScreenBounds;
    }
}

推荐答案

其他答案是正确的，Java将使用尽可能多的内存，此时它将垃圾收集。要解决此问题，可以在JVM设置中指定较小的最大堆大小。您可以使用-Xmx设置执行此操作。例如，如果您认为您只需要32MB，请将其运行为：

The other answers are right that Java will use as much memory as it is allowed to, at which point it will garbage collect. To work around this, you can specify a smaller max heap size in the JVM settings. You do this with the -Xmx setting. For example, if you think you only need 32MB, run it as:

java -Xmx32M [your main class or jar here]

你的程序堆（非堆栈内存）永远不会超过32MB，但它如果它需要更多时间会崩溃（这就是你需要配置的地方）。我没有看到你的程序有任何明显的泄漏（假设ImageIO不需要任何清理），所以我认为你没事。

The heap of your program (the non-stack memory) will never take more than 32MB, but it will crash if it needs more than that at once (and that's where you'll need to profile). I don't see any obvious leaks in your program (assuming ImageIO doesn't require any cleanup), though, so I think you'll be fine.

这篇关于为什么这个Java程序占用了这么多内存？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！