用2个线程编写程序，交替打印 [英] Writing a program with 2 threads which prints alternatively

问题描述

我最近在接受采访时被问到这个问题。

I got asked this question recently in an interview.

编写一个包含两个线程（A和B）的程序，其中A打印1，B打印2，依此类推，直到达到50.

Write a program with two threads (A and B), where A prints 1 , B prints 2 and so on until 50 is reached.

我们如何做到这一点？

推荐答案

赋值的本质是演示线程如何发出另一个信号。最常见的方法是使用阻塞队列，但这里信号不携带任何信息，因此信号量就足够了。

The essence of the assignment is to demonstrate how a thread can signal another one. Most common way is to use blocking queues, but here a signal does not carry any information, so a Semaphore is sufficient.

创建用2个信号量参数化的线程类：输入和输出：

Create thread class which is parameterized with 2 Semaphores: input and output:

class ThreadPrinter implements Runnable {
    int counter;
    Semaphore ins, outs;

    ThreadPrinter(int counter, Semaphore ins, Semaphore outs) {
        this.counter = counter;
        this.ins = ins;
        this.outs = outs;
    }

    @Override
    public void run() {
        for (int i = 0; i < 25; i++) {
            ins.aquire(); // wait for permission to run
            System.out.println("" + counter);
            outs.release();  // allow another thread to run
            counter += 2;
        }
    }

创建2 信号量 s并将它们传递给2个主题：

Create 2 Semaphores and pass them to 2 threads:

Semaphore a = new Semaphore(1);  // first thread is allowed to run immediately
Semaphore b = new Semaphore(0); // second thread has to wait
ThreadPrinter tp1 = new ThreadPrinter(1, a, b);
ThreadPrinter tp2 = new ThreadPrinter(2, b, a); 

注意信号量 a 和 b 以不同的顺序传递。

Note semaphores a and b are passed in different order.

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