使用Java的SwingWorker超时完成任务 [英] Timeout a task with Java's SwingWorker

问题描述

我正在尝试在我的应用程序中实现 SwingWorker 类。有没有办法设置一段时间，之后，SwingWorker超时？我想可能会抛出一个 OutOfTime 异常，我可以捕获然后处理。我只是不确定如何实现它。

I am trying to implement a SwingWorker class within my application. Is there a way to set a length of time that after which, the SwingWorker "times out"? I was thinking that maybe throwing an OutOfTime exception that I can catch and then deal with. I'm just not sure how to implement it.

感谢您的帮助！

推荐答案

为什么不将您的任务嵌入Runnable中，将其放入新的单线程 ExecutorService 然后对生成的 get（） ：//java.sun.com/j2se/1.5.0/docs/api/java/util/concurrent/Future.html\"rel =nofollow noreferrer>具有适当超时的未来。这将为您提供超时功能，因为 get（）将在作业未及时完成时抛出异常。

Why not embed your task within a Runnable, drop it into a new single-threaded ExecutorService and then perform a get() on the resulting Future with an appropriate timeout. That would give you your timeout functionality, since get() will throw an exception if the job doesn't complete in time.

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