如何从Java字符串中删除ANSI控件字符（VT100） [英] How to remove ANSI control chars (VT100) from a Java String

问题描述

我正在使用自动化并使用Jsch连接到远程盒并自动执行某些任务。

I am working with automation and using Jsch to connect to remote boxes and automate some tasks.

我在解析命令结果时遇到问题，因为有时它们会带有< a href =http://www.termsys.demon.co.uk/vtansi.htm =nofollow noreferrer> ANSI Control chars 。

I am having problem parsing the command results because sometimes they come with ANSI Control chars.

我已经看过这个答案和另一个但它没有提供任何图书馆都这样做。如果有的话，我不想重新发明轮子。而且我对这些答案没有信心。

I've already saw this answer and this other one but it does not provide any library to do that. I don't want to reinvent the wheel, if there is any. And I don't feel confident with those answers.

现在，我正在尝试这个，但我不确定它是否足够完整。

Right now, I am trying this, but I am not really sure it's complete enough.

reply = reply.replaceAll("\\[..;..[m]|\\[.{0,2}[m]|\\(Page \\d+\\)|\u001B\\[[K]|\u001B|\u000F", "");

如何从Java字符串中删除ANSI控制字符（VT100）？

How to remove ANSI control chars (VT100) from a Java String?

推荐答案

大多数ANSI VT100序列的格式为 ESC [，可选地后跟一个数字或两个数字，用; 分隔，然后是一些不是数字的字符或; 。所以类似

Most ANSI VT100 sequences have the format ESC [, optionally followed by a number or by two numbers separated by ;, followed by some character that is not a digit or ;. So something like

reply = reply.replaceAll("\u001B\\[[\\d;]*[^\\d;]","");

或

reply = reply.replaceAll("\\e\\[[\\d;]*[^\\d;]","");  // \e matches escape character

我应该抓住大部分内容。可能还有其他情况可以单独添加。 （我没有测试过这个。）

should catch most of them, I think. There may be other cases that you could add individually. (I have not tested this.)

你发布的正则表达式中的一些替代品以 \\ [，而不是转义字符，这可能意味着您可能正在删除一些您不应删除的文本，或者删除控制序列的一部分但是保留ESC字符。

Some of the alternatives in the regex you posted start with \\[, rather than the escape character, which may mean that you could be deleting some text you're not supposed to delete, or deleting part of a control sequence but leaving the ESC character in.

这篇关于如何从Java字符串中删除ANSI控件字符（VT100）的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！